在 Oracle 中使用 SUM 和 CASE SQL

Question

我构造了一个查询以从 2 个表中获取按日期列分组的计数。

select count(*),TO_CHAR(CREATION_DATE,'DD/Mon/YY HH') as Date_TIME,'Table_1' as TABLE_NAME
from TABLE 1
where CREATION_DATE > TO_DATE('01/10/2020','DD/MM/YYYY')
group by TO_CHAR(CREATION_DATE,'DD/Mon/YY HH')
UNION
select count(*),TO_CHAR(CREATION_DATE,'DD/Mon/YY HH') as Date_TIME , 'Table_2' as TABLE_NAME
from TABLE 2
where CREATION_DATE > TO_DATE('01/10/2020','DD/MM/YYYY')
group by TO_CHAR(CREATION_DATE,'DD/Mon/YY HH')

我想从两个表中获取结果，因此我使用了 UNION。因为我想要按 TO_CHAR(CREATION_DATE, 'DD/Mon/YY HH')

分组的计数的每小时分解

输出是这样的：

443 14/Oct/20 04    Table_1
861 14/Oct/20 04    Table_2
371 14/Oct/20 05    Table_1
323 14/Oct/20 06    Table_2

如您所见，我希望输出 counts summed up hour[=31] =] 从两个表中得出这样的结果：

1304 14/Oct/20 04 Table_1 371 14/Oct/20 05 Table_1 323 14/Oct/20 06 Table_2

我可以做到这一点excel，但不实用。我在考虑 Oracle 中的 CASE 语句，但从未真正实现它。

数据库：甲骨文编辑：Toad for Oracle

Answer 1

使用您当前的查询作为最终结果的数据源：

  SELECT SUM (cnt) sum_cnt, date_time, MAX (table_name) table_name
    FROM (  SELECT COUNT (*) cnt,
                   TO_CHAR (creation_date, 'DD/Mon/YY HH') AS date_time,
                   'Table_1' AS table_name
              FROM TABLE_1
             WHERE creation_date > TO_DATE ('01/10/2020', 'DD/MM/YYYY')
          GROUP BY TO_CHAR (creation_date, 'DD/Mon/YY HH')
          UNION
            SELECT COUNT (*),
                   TO_CHAR (creation_date, 'DD/Mon/YY HH') AS date_time,
                   'Table_2' AS table_name
              FROM TABLE_2
             WHERE creation_date > TO_DATE ('01/10/2020', 'DD/MM/YYYY')
          GROUP BY TO_CHAR (creation_date, 'DD/Mon/YY HH'))
GROUP BY date_time
ORDER BY date_time, table_name

在 Oracle 中使用 SUM 和 CASE SQL

Using SUM and CASE in Oracle SQL

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