neo4j-graphql-js 自定义 return @cypher 查询类型

Question

我正在尝试扩展使用 neo4j-graphql-js

自动生成的 graphql 模式

这是我的 graphql 模式

typeDefs

type Person {
   _id: Long!
   addresslocation: Point!
   confirmedtime: DateTime!
   healthstatus: String!
   id: String!
   name: String!
   performs_visit: [Visit] @relation(name: "PERFORMS_VISIT", direction: OUT)
   visits: [Place] @relation(name: "VISITS", direction: OUT)
   VISITS_rel: [VISITS]
}

type Place {
   _id: Long!
   homelocation: Point!
   id: String!
   name: String!
   type: String!
   part_of: [Region] @relation(name: "PART_OF", direction: OUT)
   visits: [Visit] @relation(name: "LOCATED_AT", direction: IN)
   persons: [Person] @relation(name: "VISITS", direction: IN)
}

type Visit {
   _id: Long!
   duration: String!
   endtime: DateTime!
   id: String!
   starttime: DateTime!
   located_at: [Place] @relation(name: "LOCATED_AT", direction: OUT)
   persons: [Person] @relation(name: "PERFORMS_VISIT", direction: IN)
}

type Region {
   _id: Long!
   name: String!
   places: [Place] @relation(name: "PART_OF", direction: IN)
}

type Country {
   _id: Long!
   name: String!
}

type Continent {
   _id: Long!
   name: String!
}



type VISITS @relation(name: "VISITS") {
  from: Person!
  to: Place!
  duration: String!
  endtime: DateTime!
  id: String!
  starttime: DateTime!
}

现在我扩展 Person 来执行自定义查询，为此我使用 @cypher 指令

typeDefs2

type Person {
        potentialSick: [Person] @cypher(statement: """
            MATCH (p:this)--(v1:Visit)--(pl:Place)--(v2:Visit)--(p2:Person {healthstatus:"Healthy"})
            return *
        """)
  }

我通过合并两个 typeDef 创建了模式，它按预期工作

export const schema = makeAugmentedSchema({
    typeDefs: mergeTypeDefs([typeDefs, typeDefs2]),
    config: {
        debug: true,
    },
});

问题

可以从我的自定义查询 return 自定义类型（在 graphql 中映射）potentialSick ?

我的目标是return一个类似于这个的类型

type PotentialSick {
    id: ID
    name: String
    overlapPlaces: [Place] 
}

重叠的地方是我的 neo4j 查询中的 pl

MATCH (p:this)--(v1:Visit)--(pl:Place)--(v2:Visit)--(p2:Person {healthstatus:"Healthy"})

Answer 1

我意识到 neo4j-graphql-js 是一个查询生成器，所以我可以通过使用 graphql 仅使用主模式来获取我的数据。我的查询将是：

{
  Person(filter: { healthstatus: "Sick" }) {
    id
    visits {
      _id
      persons(filter: { healthstatus: "Healthy" }) {
        _id
      }
    }
  }
}

对于需要 @cyper 的更复杂查询，考虑到这一原则，我可以扩展每种类型的基本模式并依赖 graphql 功能

举个例子

type Person {
        potentialSick: [Place] @cypher(statement: """
            MATCH path =(this)-[:VISITS]->(place:Place)<-[:VISITS]-(p2:Person {healthstatus:"Healthy"})
            return place
        """)

potentialSick return places 然后为了获得访问那个地方的人我可以使用 graphql

{
  Person(filter: { healthstatus: "Sick" }) {
    id
    potentialSick {
      persons (filter: { healthstatus: "Healthy" }){
        _id
      }
    }
  }
}

neo4j-graphql-js 自定义 return @cypher 查询类型

neo4j-graphql-js custom return type for @cypher query

neo4j

graphql

neo4j-graphql-js