在 sed 中的匹配模式之后附加一行不起作用
Appending a line just after the matched pattern in sed not working
我的 /etc/pam.d/system-auth-ac
设置了以下 auth
参数:
auth required pam_env.so
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我想在 pam_env.so
之后插入 pam_tally2.so
。所以我希望它是:
auth required pam_env.so
auth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我使用的脚本是:
#! /bin/bash
grep "pam_tally2" /etc/pam.d/system-auth-ac &> /dev/null
if [ $? -ne 0 ];
then
sed -i '/^[]*account[]*required[]*pam_unix.so/aauth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' /etc/pam.d/system-auth-ac
else
sed -i 's/.*pam_tally2.*/auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900/1' /etc/pam.d/system-auth-ac
fi
但它给出了这个错误:
sed: -e expression #1, char 116: unterminated address regex
我做错了什么?
您可以使用下面的 sed 命令。
sed 's/^auth[[:blank:]]\+required[[:blank:]]\+pam_env\.so/&\nauth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' file
您的正则表达式失败,因为您重复空字符 class []
零次或多次,这没有任何意义。因此,您需要将 []*
更改为 [ ]*
或 <space>*
以重复空 space 字符零次或多次。
您可以在 gnu-sed 中使用 a
命令:
sed -i.bak '/pam_env\.so$/a\
auth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
' /etc/pam.d/system-auth-ac
编辑: 查看您发布的答案似乎这个 awk
命令比 grep
和 2 sed
更适合您if/else
条件下的命令:
val='auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900'
awk -v val="$val" '/^auth[[:blank:]]+required[[:blank:]]+pam_env\.so/ {
print [=11=] RS val; next} /pam_tally2\.so/{next} 1' /etc/pam.d/system-auth-ac
auth required pam_env.so
uth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我的脚本实际上应该是:
#! /bin/bash
grep "pam_tally2" /etc/pam.d/system-auth-ac &> /dev/null
if [ $? -ne 0 ];
then
sed -i '/^[ ]*auth[ ]*required[ ]*pam_env.so/aauth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' /etc/pam.d/system-auth-ac
else
sed -i 's/.*pam_tally2.*/auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900/1' /etc/pam.d/system-auth-ac
fi
工作正常!
我的 /etc/pam.d/system-auth-ac
设置了以下 auth
参数:
auth required pam_env.so
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我想在 pam_env.so
之后插入 pam_tally2.so
。所以我希望它是:
auth required pam_env.so
auth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我使用的脚本是:
#! /bin/bash
grep "pam_tally2" /etc/pam.d/system-auth-ac &> /dev/null
if [ $? -ne 0 ];
then
sed -i '/^[]*account[]*required[]*pam_unix.so/aauth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' /etc/pam.d/system-auth-ac
else
sed -i 's/.*pam_tally2.*/auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900/1' /etc/pam.d/system-auth-ac
fi
但它给出了这个错误:
sed: -e expression #1, char 116: unterminated address regex
我做错了什么?
您可以使用下面的 sed 命令。
sed 's/^auth[[:blank:]]\+required[[:blank:]]\+pam_env\.so/&\nauth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' file
您的正则表达式失败,因为您重复空字符 class []
零次或多次,这没有任何意义。因此,您需要将 []*
更改为 [ ]*
或 <space>*
以重复空 space 字符零次或多次。
您可以在 gnu-sed 中使用 a
命令:
sed -i.bak '/pam_env\.so$/a\
auth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
' /etc/pam.d/system-auth-ac
编辑: 查看您发布的答案似乎这个 awk
命令比 grep
和 2 sed
更适合您if/else
条件下的命令:
val='auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900'
awk -v val="$val" '/^auth[[:blank:]]+required[[:blank:]]+pam_env\.so/ {
print [=11=] RS val; next} /pam_tally2\.so/{next} 1' /etc/pam.d/system-auth-ac
auth required pam_env.so
uth required pam_tally2.so onerr=fail audit silent deny=5 unlock_time=900
auth sufficient pam_unix.so nullok try_first_pass
auth requisite pam_succeed_if.so uid >= 500 quiet
auth required pam_deny.so
我的脚本实际上应该是:
#! /bin/bash
grep "pam_tally2" /etc/pam.d/system-auth-ac &> /dev/null
if [ $? -ne 0 ];
then
sed -i '/^[ ]*auth[ ]*required[ ]*pam_env.so/aauth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900' /etc/pam.d/system-auth-ac
else
sed -i 's/.*pam_tally2.*/auth\trequired\tpam_tally2.so onerr=fail audit silent deny=5 unlock_time=900/1' /etc/pam.d/system-auth-ac
fi
工作正常!