不确定如何从屏幕上默认显示中删除此 FlatList
Not sure how to remove this FlatList from displaying by default on screen
目前,这种 - is how the SearchBar and FlatList is showing up on the screen. Upon clicking on the SearchBar and typing one of the list components, it shows up this- 方式。我希望 FlatList 仅在我单击 SearchBar 时出现。我如何在应用程序中实现它?类似下拉搜索栏的东西...
import React from 'react';
import { View, Text, FlatList, ActivityIndicator, StyleSheet } from 'react-native';
import { SearchBar } from 'react-native-elements';
import { Button, Menu, Divider, Provider, TextInput } from 'react-native-paper';
const restaurantList = [
{
type: 'Italian',
name: 'DiMaggio'
},
{
type: 'Greek',
name: 'Athena'
}
];
export default class App extends React.Component {
static navigationOptions = {
title: 'Search for Restaurants'
};
constructor (props) {
super(props);
this.state = {
loading: false,
data: restaurantList,
error: null,
value: '',
};
this.arrayholder = [];
}
renderSeparator = () => {
return (
<View
style={{
height: 1,
width: '86%',
backgroundColor: '#CED0CE',
marginLeft: '14%'
}}
/>
);
};
searchFilterFunction = text => {
this.setState({
value: text
});
const newData = restaurantList.filter(item => {
console.log(item.type)
const itemData = `${item.name.toUpperCase()} ${item.type.toUpperCase()}`;
const textData = text.toUpperCase();
return itemData.includes(textData);
});
this.setState({
data: newData
});
};
renderHeader = () => {
return (
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
/>
);
};
render () {
if (this.state.loading) {
return (
<View style={{ flex: 1, alignItems: 'center', justifyContent: 'center' }}>
<ActivityIndicator />
</View>
);
} else {
return (
<Provider>
<View
style={{
paddingTop: 50,
flexDirection: 'row',
justifyContent: 'center',
}}>
<View style={styles.container}>
<FlatList
keyExtractor={(item, index) => `${index}`}
extraData={this.state}
data={this.state.data}
renderItem={({ item }) => (
<Text>{item.name} {item.type}</Text>
)}
ItemSeparatorComponent={this.renderSeparator}
ListHeaderComponent={this.renderHeader}
/>
</View>
</View>
<View style={styles.container}>
<TextInput />
</View>
</Provider>
);
}
}
}
试试这个方法
this.state = {
searchClicked: false
};
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
onFocus={() => this.setState({searchClicked: true})}
onBlur={() => this.setState({searchClicked: false})}
/>
<View>{this.renderHeader()}</View>
{this.state.searchClicked && <FlatList
keyExtractor={(item, index) => `${index}`}
extraData={this.state}
data={this.state.data}
renderItem={({ item }) => (
<Text>{item.name} {item.type}</Text>
)}
ItemSeparatorComponent={this.renderSeparator}
// ListHeaderComponent={this.renderHeader} <—- Remove from here —->
/>}
如果@Lakhani 的回复不能满足你的问题,我有另一个建议给你。
您的 SearchBar 应该包含 TextInput
。您可以使用 onFocus
和 onBlur
道具来捕获您点击 SearchBar 或离开它的事件。
...
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
onFocus={()=>this.setState({showList: true})} // <---
onBlur={()=>this.setState({showList: false})} // <---
/>
...
render() {
return (
...
{
this.state.showList && <FlatList ... />
}
)
}
目前,这种 -
import React from 'react';
import { View, Text, FlatList, ActivityIndicator, StyleSheet } from 'react-native';
import { SearchBar } from 'react-native-elements';
import { Button, Menu, Divider, Provider, TextInput } from 'react-native-paper';
const restaurantList = [
{
type: 'Italian',
name: 'DiMaggio'
},
{
type: 'Greek',
name: 'Athena'
}
];
export default class App extends React.Component {
static navigationOptions = {
title: 'Search for Restaurants'
};
constructor (props) {
super(props);
this.state = {
loading: false,
data: restaurantList,
error: null,
value: '',
};
this.arrayholder = [];
}
renderSeparator = () => {
return (
<View
style={{
height: 1,
width: '86%',
backgroundColor: '#CED0CE',
marginLeft: '14%'
}}
/>
);
};
searchFilterFunction = text => {
this.setState({
value: text
});
const newData = restaurantList.filter(item => {
console.log(item.type)
const itemData = `${item.name.toUpperCase()} ${item.type.toUpperCase()}`;
const textData = text.toUpperCase();
return itemData.includes(textData);
});
this.setState({
data: newData
});
};
renderHeader = () => {
return (
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
/>
);
};
render () {
if (this.state.loading) {
return (
<View style={{ flex: 1, alignItems: 'center', justifyContent: 'center' }}>
<ActivityIndicator />
</View>
);
} else {
return (
<Provider>
<View
style={{
paddingTop: 50,
flexDirection: 'row',
justifyContent: 'center',
}}>
<View style={styles.container}>
<FlatList
keyExtractor={(item, index) => `${index}`}
extraData={this.state}
data={this.state.data}
renderItem={({ item }) => (
<Text>{item.name} {item.type}</Text>
)}
ItemSeparatorComponent={this.renderSeparator}
ListHeaderComponent={this.renderHeader}
/>
</View>
</View>
<View style={styles.container}>
<TextInput />
</View>
</Provider>
);
}
}
}
试试这个方法
this.state = {
searchClicked: false
};
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
onFocus={() => this.setState({searchClicked: true})}
onBlur={() => this.setState({searchClicked: false})}
/>
<View>{this.renderHeader()}</View>
{this.state.searchClicked && <FlatList
keyExtractor={(item, index) => `${index}`}
extraData={this.state}
data={this.state.data}
renderItem={({ item }) => (
<Text>{item.name} {item.type}</Text>
)}
ItemSeparatorComponent={this.renderSeparator}
// ListHeaderComponent={this.renderHeader} <—- Remove from here —->
/>}
如果@Lakhani 的回复不能满足你的问题,我有另一个建议给你。
您的 SearchBar 应该包含 TextInput
。您可以使用 onFocus
和 onBlur
道具来捕获您点击 SearchBar 或离开它的事件。
...
<SearchBar
placeholder="Type..."
value={this.state.value}
onChangeText={text => this.searchFilterFunction(text)}
onFocus={()=>this.setState({showList: true})} // <---
onBlur={()=>this.setState({showList: false})} // <---
/>
...
render() {
return (
...
{
this.state.showList && <FlatList ... />
}
)
}