在两个类 "QWidget" 之间共享属性

Question

我正在尝试将属性从 QWidget class“发送”到另一个。

在下面的示例中，我尝试将属于 class“Widget1”的 QLineEdit“self.edit”的文本设置为 QLabel“self.label”的文本”属于 class“Widget2”。

此尝试是在函数“setLabel”中进行的。我无法弄清楚的部分是“Widget2.label.setText(text)”

在一个函数的 class 中有一个 class...我有点困惑如何实现它...

import sys
from PySide2.QtWidgets import (QApplication, QHBoxLayout, QVBoxLayout, QWidget, QPushButton, QLabel, QLineEdit)

class Main_UI(QWidget):

    def __init__(self):
        super().__init__()
        self.initUI()

    def initUI(self):
        layout = QVBoxLayout()
        widget1 = Widget1()
        widget2 = Widget2()
        layout.addWidget(widget1)
        layout.addWidget(widget2)
        self.setLayout(layout)
        self.show()

class Widget1(QWidget):
    def __init__(self):
        super().__init__()
        self.initUI()

    def initUI(self):
        layout = QHBoxLayout()
        self.edit = QLineEdit("")
        button = QPushButton("Set value")
        button.clicked.connect(self.setLabel)
        layout.addWidget(self.edit)
        layout.addWidget(button)
        self.setLayout(layout)
    
    def setLabel(self):
        text = self.edit.text()
        Widget2.label.setText(text)

class Widget2(QWidget):
    def __init__(self):
        super().__init__()
        self.initUI()

    def initUI(self):
        layout = QHBoxLayout()
        self.label = QLabel("")
        layout.addWidget(self.label)
        self.setLayout(layout)

def main():
    app = QApplication(sys.argv)
    ex = Main_UI()
    sys.exit(app.exec_())

if __name__ == '__main__':
    main()

任何帮助将不胜感激，如果我的示例或解释不清楚，我将提供进一步的解释。

Answer 1

您可以使用自定义信号执行此操作。

import sys
from PyQt5.QtWidgets import (QApplication, QHBoxLayout, QVBoxLayout, QWidget, QPushButton, QLabel, QLineEdit)
from PyQt5 import QtCore


class Main_UI(QWidget):
    def __init__(self, parent=None):
        super(Main_UI, self).__init__(parent)
        self.initUI()
    
    def initUI(self):
        layout = QVBoxLayout()
        widget1 = Widget1()
        widget2 = Widget2()
        layout.addWidget(widget1)
        layout.addWidget(widget2)
        self.setLayout(layout)
        
        widget1.button_signal.connect(widget2.label.setText)  # Connecting the label to the custom signal.
        
        self.show()


class Widget1(QWidget):
    button_signal = QtCore.pyqtSignal(str)  # Creating a signal.
    
    def __init__(self, parent=None):
        super(Widget1, self).__init__(parent)
        self.initUI()
    
    def initUI(self):
        layout = QHBoxLayout()
        self.edit = QLineEdit("")
        button = QPushButton("Set value")
        button.clicked.connect(self.setLabel)
        layout.addWidget(self.edit)
        layout.addWidget(button)
        self.setLayout(layout)
    
    def setLabel(self):
        """Emit button signal with text.
        
        This could have been solved with a lambda.
        
        """        
        self.button_signal.emit(self.edit.text())  # Emitting Signal.


class Widget2(QWidget):
    def __init__(self, parent=None):
        super(Widget2, self).__init__(parent)
        self.initUI()
    
    def initUI(self):
        layout = QHBoxLayout()
        self.label = QLabel("")
        layout.addWidget(self.label)
        self.setLayout(layout)


def main():
    app = QApplication(sys.argv)
    ex = Main_UI()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

文档：https://doc.qt.io/qt-5/signalsandslots.html

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