多少n长的二进制序列问题
how many n-length binary sequence problem
如何在 python/java 或任何其他语言中找到此问题的解决方案:
提前致谢
由于程序不是证明,您仍然需要证明它,这里是一些 Python 代码:
def zig_zag(seq):
"""tests if binary sequence seq satsifies zig-zag pattern"""
for i in range(len(seq)-1):
if (i%2 == 0 and seq[i] > seq[i+1]) or (i%2 == 1 and seq[i] < seq[i+1]):
return False
return True
def count_zig_zags(n):
"""counts the number of binary zig-zag patterns of length n"""
count = 0
for i in range(2**n):
b = bin(i)[2:]
if zig_zag(b): count += 1
return count
例如:
>>> [count_zig_zags(n) for n in range(1,12)]
[2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233]
证明将通过强归纳法。
如何在 python/java 或任何其他语言中找到此问题的解决方案:
提前致谢
由于程序不是证明,您仍然需要证明它,这里是一些 Python 代码:
def zig_zag(seq):
"""tests if binary sequence seq satsifies zig-zag pattern"""
for i in range(len(seq)-1):
if (i%2 == 0 and seq[i] > seq[i+1]) or (i%2 == 1 and seq[i] < seq[i+1]):
return False
return True
def count_zig_zags(n):
"""counts the number of binary zig-zag patterns of length n"""
count = 0
for i in range(2**n):
b = bin(i)[2:]
if zig_zag(b): count += 1
return count
例如:
>>> [count_zig_zags(n) for n in range(1,12)]
[2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233]
证明将通过强归纳法。