如何将列表索引（网格）与片段元素进行比较？

Question

grid = []
piece = ( (0, 0), (0, 1), (0, 2), (0, 3) )

for f in range(18):
    grilla_vacia.append([])
    for c in range(9):
        if [f][c] in piece:
            grilla_vacia[f].append(1)
        grilla_vacia[f].append(0)

如何在格子中'busy'的位置加'1'？注释行抛出了这个错误：'list index out of range'

Answer 1

这应该对您有帮助：

import numpy as np

piece = ( (0, 0), (0, 1), (0, 2), (0, 3) )
grid = np.zeros((9,18),dtype=int).tolist()

for p in piece:
    grid[p[1]][p[0]] = 1

print(grid)

输出：

[[1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0]]

这是一个没有numpy的解决方案：

piece = ( (0, 0), (0, 1), (0, 2), (0, 3) )

grid = [0 for x in range(9*18)]
grid = [grid[i:i+9] for i in range(0, len(grid), 9)]

for p in piece:
    grid[p[1]][p[0]] = 1

print(grid)

输出：

[[1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0]]

如何将列表索引（网格）与片段元素进行比较？

How to compare a list indice (grid), with piece elements?

list

python-3.6

python-3.7

indices