我如何 [=10a 重复两个属性的行

Question

我有一个 table 与 Destino 和 Tronco，Fecha，我需要将重复的 Destino 和 Tronco 分组

SELECT Destino
    ,Tronco
    ,Count(*) AS Countrows
FROM Hist_LDS
WHERE Fecha = '2020-10-28'
GROUP BY Destino
    ,Tronco
HAVING COUNT(*) > 1

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结果为空但是如果我 Select 没有计数，它就会消失

SELECT Destino
    ,Tronco
FROM Hist_LDS
WHERE Fecha = '2020-10-28'

enter image description here

Answer 1

你是说 Destino 还是 Tronco 重复？您目前正在做的是寻找它们两者组合的重复 - 这在您的示例数据列表中不存在。

如果是，请查看以下内容是否returns您所追求的。

如果没有，请提供样本数据，包括您认为应该出现在初始查询中的记录。

--Identify duplicated Tronco values
select Tronco, Count(*) As Countrows
INTO #TRONCO
From Hist_LDS
Where Fecha='2020-10-28' 
GROUP BY Tronco
HAVING COUNT (*)>1

--Identify duplicated Destino values
select Destino, Count(*) As Countrows
INTO #DESTINO
From Hist_LDS
Where Fecha='2020-10-28' 
GROUP BY DESTINO
HAVING COUNT (*)>1


--Identify records from initial table where Destino or Tronco were repeated
select Destino, Tronco, Count(*) As Countrows
From Hist_LDS
Where Fecha='2020-10-28' 
AND (Destino in (SELECT destino from #DESTINO) OR Tronco in (SELECT tronco from #TRONCO))

我如何 [=10a 重复两个属性的行

how can I select a rows that repets two atributtes

sql

select

counting