无法使用具有 strong_parameters 和嵌套属性的 POST 更新或创建记录
Unable to update or create records using POST with strong_parameters and nested attributes
我不明白为什么我的数据库记录没有更新，或者没有创建新记录，就此而言，当我从表单中 POST 时。
我能够手动填充数据库并创建关系：
contact = Contact.first
command = Command.find(3)
contact.host_notification_commands << command
而且我还能够将此数据信息加载到我的表单中。我想不通的是如何更新或添加新记录。到目前为止我尝试过的一切都失败了。
我有 3 个模型 - Command、Contact 并加入了 CommandsContact。 commands_contacts join table 正在保留一个额外的属性 :notification_type，可以将其设置为 host 或 service，我的 Contact 模型有 2 个额外的关系设置，我可以访问 :host_notification_commands 和 :service_notification_commands。这使我能够执行 Contact.fist.host_notification_commands 或 Contact.find(3).service_notification_commands.
之类的操作
似乎没有 UPDATE 或 INSERT 查询从控制器启动，当我正确 POST 并且我不知道如何调试它时。
型号
class Command < ActiveRecord::Base
has_many :commands_contacts
has_many :contacts, :through => :commands_contacts
end
class Contact < ActiveRecord::Base
has_many :commands_contacts
has_many :commands, :through => :commands_contacts
has_many :host_notification_commands, -> { where commands_contacts: { :notification_type => 'host' } },
:through => :commands_contacts,
:class_name => 'Command',
:source => :command
has_many :service_notification_commands, -> { where commands_contacts: { notification_type: 'service' } },
:through => :commands_contacts,
:class_name => 'Command',
:source => :command
accepts_nested_attributes_for :commands, :host_notification_commands, :service_notification_commands
end
class CommandsContact < ActiveRecord::Base
belongs_to :command
belongs_to :contact
accepts_nested_attributes_for :command
end
然后一切都崩溃了。
控制器
由于我使用的是 accepts_nested_attributes_for，因此我必须将 _attributes 附加到我的嵌套对象的名称 - :host_notification_commands 和 :service_notification_commands。我将更改我的表单以这种方式提交，但简单的重新分配只是为了举例。
def update
contact = Contact.find_by_id(params[:id])
contact.update(safe_params)
end
private
def safe_params
params[:contact][:host_notification_commands_attributes] = params[:contact][:host_notification_commands]
params[:contact][:service_notification_commands_attributes] = params[:contact][:service_notification_commands]
params.require(:contact)
.permit(:contact_name, :host_notification_commands_attributes => [:id, :command_name, :command_line, :command_description],
:service_notification_commands_attributes => [:id, :command_name, :command_line, :command_description])
end
更新现有记录结果：
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=2 for Contact with ID=1>
当然不存在！我正在努力建立这种关系！
添加一个新的，我得到：
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=1 for Contact with ID=>
完全正确。甚至还没有创建用户，也没有与命令建立关系，为什么 Rails 试图找到它？？？
我也没有看到任何更新或插入查询被记录在 rails 控制台中，所以我想它甚至没有达到那个点...
D, [2015-01-20T18:01:30.336669 #95542] DEBUG -- : (0.1ms) BEGIN
D, [2015-01-20T18:01:30.338971 #95542] DEBUG -- : Command Load (0.3ms) SELECT `commands`.* FROM `commands` INNER JOIN `commands_contacts` ON `commands`.`id` = `commands_contacts`.`command_id` WHERE `commands_contacts`.`contact_id` = 1 AND `commands_contacts`.`notification_type` = 'host' AND `commands`.`id` IN (1, 3)
D, [2015-01-20T18:01:30.340555 #95542] DEBUG -- : Command Load (0.2ms) SELECT `commands`.* FROM `commands` INNER JOIN `commands_contacts` ON `commands`.`id` = `commands_contacts`.`command_id` WHERE `commands_contacts`.`contact_id` = 1 AND `commands_contacts`.`notification_type` = 'service' AND `commands`.`id` IN (4, 2)
D, [2015-01-20T18:01:30.341501 #95542] DEBUG -- : (0.1ms) ROLLBACK
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=2 for Contact with ID=1>
Completed 200 OK in 11ms (Views: 0.4ms | ActiveRecord: 0.9ms)
我在这里错过了什么？
编辑： 我想我可以放弃使用 strong_parameters 的想法，解析所有 POST 参数然后手动填充数据库，但事实并非如此非常 Rails-y.
编辑 #2: 包括发布到控制器的参数。
数据以 params[:contact] 形式从表单
中传入
{
"contact_name" => "joe-user",
"host_notification_commands" => [
[0] {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert",
"created_at" => "2015-01-19T17:24:12.000Z",
"updated_at" => "2015-01-21T03:29:03.000Z"
},
[1] {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager",
"created_at" => "2015-01-19T17:24:33.000Z",
"updated_at" => "2015-01-19T17:24:33.000Z"
}
],
"service_notification_commands" => [
[0] {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert",
"created_at" => "2015-01-19T17:24:44.000Z",
"updated_at" => "2015-01-19T17:24:44.000Z"
}
]
}
经过strong_parameters后变成这样：
本质上是一样的，只是去掉了 created_at 和 updated_at 并且
_attributes 附加到属性名称，因此它适用于 accept_nested_attributes_for
{
"contact_name" => "joe-user",
"host_notification_commands_attributes" => [
[0] {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert"
},
[1] {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager"
}
],
"service_notification_commands_attributes" => [
[0] {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
}
]
}
编辑 #3： 我启用了 MySQL 查询日志记录，但我根本没有看到 UPDATE/INSERT 查询执行。我如何调试为什么 contact.update(safe_params) 没有做任何事情？
编辑 #4: 作为一个没有 AngularJS 或 POST 的简单测试，我做了一个简单的 rake 任务，它定义了一个 JSON 对象并尝试更新数据库。我遇到了同样的问题，所以我很确定问题出在我的模型中...但是在哪里？？？
请看一下这个 Gist https://gist.github.com/pruchai/6afe74b170da2a3d307f
构建表单并使用 nested_fields_for 时，您的表单结构构建正确。所以理想情况下，你会先尝试做 "old fashioned way"，检查推送到服务器的内容并模仿它。
所以通常我不会手动执行此操作，但我会维护一个 gem 来处理嵌套表单（茧），所以如果我没记错的话，为了使 accepts_nested_attributes 起作用，参数必须如下所示：
{
"contact_name" => "joe-user",
"host_notification_commands_attributes" => {
"0" => {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert"
},
"1" => {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager"
}
},
"service_notification_commands_attributes" => {
"0" => {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
},
"12342233444444" => {
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
}
}
}
所以 .._attributes 应该包含一个散列而不是一个数组。关键只是（现有）数组中的位置，我假设。在 cocoon 中，我用从当前时间派生的一些大数字填充这个 虚拟索引 。我假设这个顺序应该对应于关系的默认顺序。但是，如果您传递 "id" 字段，则 rails 也可能使用它。不确定。要销毁现有元素，您必须设置 _destroy 属性（并在强参数中也允许它）。
恕我直言，对于新项目，id 应该为空，否则 rails 将假定该项目存在（因为通常不会在客户端生成 ID）。
我不明白为什么我的数据库记录没有更新，或者没有创建新记录，就此而言，当我从表单中 POST 时。
我能够手动填充数据库并创建关系：
contact = Contact.first
command = Command.find(3)
contact.host_notification_commands << command
而且我还能够将此数据信息加载到我的表单中。我想不通的是如何更新或添加新记录。到目前为止我尝试过的一切都失败了。
我有 3 个模型 - Command、Contact 并加入了 CommandsContact。 commands_contacts join table 正在保留一个额外的属性 :notification_type，可以将其设置为 host 或 service，我的 Contact 模型有 2 个额外的关系设置，我可以访问 :host_notification_commands 和 :service_notification_commands。这使我能够执行 Contact.fist.host_notification_commands 或 Contact.find(3).service_notification_commands.
似乎没有 UPDATE 或 INSERT 查询从控制器启动，当我正确 POST 并且我不知道如何调试它时。
型号
class Command < ActiveRecord::Base
has_many :commands_contacts
has_many :contacts, :through => :commands_contacts
end
class Contact < ActiveRecord::Base
has_many :commands_contacts
has_many :commands, :through => :commands_contacts
has_many :host_notification_commands, -> { where commands_contacts: { :notification_type => 'host' } },
:through => :commands_contacts,
:class_name => 'Command',
:source => :command
has_many :service_notification_commands, -> { where commands_contacts: { notification_type: 'service' } },
:through => :commands_contacts,
:class_name => 'Command',
:source => :command
accepts_nested_attributes_for :commands, :host_notification_commands, :service_notification_commands
end
class CommandsContact < ActiveRecord::Base
belongs_to :command
belongs_to :contact
accepts_nested_attributes_for :command
end
然后一切都崩溃了。
控制器
由于我使用的是 accepts_nested_attributes_for，因此我必须将 _attributes 附加到我的嵌套对象的名称 - :host_notification_commands 和 :service_notification_commands。我将更改我的表单以这种方式提交，但简单的重新分配只是为了举例。
def update
contact = Contact.find_by_id(params[:id])
contact.update(safe_params)
end
private
def safe_params
params[:contact][:host_notification_commands_attributes] = params[:contact][:host_notification_commands]
params[:contact][:service_notification_commands_attributes] = params[:contact][:service_notification_commands]
params.require(:contact)
.permit(:contact_name, :host_notification_commands_attributes => [:id, :command_name, :command_line, :command_description],
:service_notification_commands_attributes => [:id, :command_name, :command_line, :command_description])
end
更新现有记录结果：
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=2 for Contact with ID=1>
当然不存在！我正在努力建立这种关系！
添加一个新的，我得到：
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=1 for Contact with ID=>
完全正确。甚至还没有创建用户，也没有与命令建立关系，为什么 Rails 试图找到它？？？
我也没有看到任何更新或插入查询被记录在 rails 控制台中，所以我想它甚至没有达到那个点...
D, [2015-01-20T18:01:30.336669 #95542] DEBUG -- : (0.1ms) BEGIN
D, [2015-01-20T18:01:30.338971 #95542] DEBUG -- : Command Load (0.3ms) SELECT `commands`.* FROM `commands` INNER JOIN `commands_contacts` ON `commands`.`id` = `commands_contacts`.`command_id` WHERE `commands_contacts`.`contact_id` = 1 AND `commands_contacts`.`notification_type` = 'host' AND `commands`.`id` IN (1, 3)
D, [2015-01-20T18:01:30.340555 #95542] DEBUG -- : Command Load (0.2ms) SELECT `commands`.* FROM `commands` INNER JOIN `commands_contacts` ON `commands`.`id` = `commands_contacts`.`command_id` WHERE `commands_contacts`.`contact_id` = 1 AND `commands_contacts`.`notification_type` = 'service' AND `commands`.`id` IN (4, 2)
D, [2015-01-20T18:01:30.341501 #95542] DEBUG -- : (0.1ms) ROLLBACK
#<ActiveRecord::RecordNotFound: Couldn't find Command with ID=2 for Contact with ID=1>
Completed 200 OK in 11ms (Views: 0.4ms | ActiveRecord: 0.9ms)
我在这里错过了什么？
编辑： 我想我可以放弃使用 strong_parameters 的想法，解析所有 POST 参数然后手动填充数据库，但事实并非如此非常 Rails-y.
编辑 #2: 包括发布到控制器的参数。
数据以 params[:contact] 形式从表单
{
"contact_name" => "joe-user",
"host_notification_commands" => [
[0] {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert",
"created_at" => "2015-01-19T17:24:12.000Z",
"updated_at" => "2015-01-21T03:29:03.000Z"
},
[1] {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager",
"created_at" => "2015-01-19T17:24:33.000Z",
"updated_at" => "2015-01-19T17:24:33.000Z"
}
],
"service_notification_commands" => [
[0] {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert",
"created_at" => "2015-01-19T17:24:44.000Z",
"updated_at" => "2015-01-19T17:24:44.000Z"
}
]
}
经过strong_parameters后变成这样：
本质上是一样的，只是去掉了 created_at 和 updated_at 并且
_attributes 附加到属性名称，因此它适用于 accept_nested_attributes_for
{
"contact_name" => "joe-user",
"host_notification_commands_attributes" => [
[0] {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert"
},
[1] {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager"
}
],
"service_notification_commands_attributes" => [
[0] {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
}
]
}
编辑 #3： 我启用了 MySQL 查询日志记录，但我根本没有看到 UPDATE/INSERT 查询执行。我如何调试为什么 contact.update(safe_params) 没有做任何事情？
编辑 #4: 作为一个没有 AngularJS 或 POST 的简单测试，我做了一个简单的 rake 任务，它定义了一个 JSON 对象并尝试更新数据库。我遇到了同样的问题，所以我很确定问题出在我的模型中...但是在哪里？？？
请看一下这个 Gist https://gist.github.com/pruchai/6afe74b170da2a3d307f
构建表单并使用 nested_fields_for 时，您的表单结构构建正确。所以理想情况下，你会先尝试做 "old fashioned way"，检查推送到服务器的内容并模仿它。
所以通常我不会手动执行此操作，但我会维护一个 gem 来处理嵌套表单（茧），所以如果我没记错的话，为了使 accepts_nested_attributes 起作用，参数必须如下所示：
{
"contact_name" => "joe-user",
"host_notification_commands_attributes" => {
"0" => {
"id" => 1,
"command_name" => "host-notify-by-email",
"command_line" => "/usr/local/bin/host-notify",
"command_description" => "Host Alert"
},
"1" => {
"id" => 2,
"command_name" => "host-notify-by-pager",
"command_line" => "/usr/local/bin/host-notify-pager",
"command_description" => "Host Alert by Pager"
}
},
"service_notification_commands_attributes" => {
"0" => {
"id" => 4,
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
},
"12342233444444" => {
"command_name" => "service-notify-by-email",
"command_line" => "/usr/local/bin/service-notify",
"command_description" => "Service Alert"
}
}
}
所以 .._attributes 应该包含一个散列而不是一个数组。关键只是（现有）数组中的位置，我假设。在 cocoon 中，我用从当前时间派生的一些大数字填充这个 虚拟索引 。我假设这个顺序应该对应于关系的默认顺序。但是，如果您传递 "id" 字段，则 rails 也可能使用它。不确定。要销毁现有元素，您必须设置 _destroy 属性（并在强参数中也允许它）。
恕我直言，对于新项目，id 应该为空，否则 rails 将假定该项目存在（因为通常不会在客户端生成 ID）。