创建一个带有副标题的 ggplotly object
Create a ggplotly object with a subtitle
我正在用 ggplot()
绘制散点图,如下所示:
library(data.table)
library(plotly)
library(ggplot2)
library(lubridate)
dt.allData <- data.table(date = seq(as.Date('2020-01-01'), by = '1 day', length.out = 365),
DE = rnorm(365, 4, 1), Austria = rnorm(365, 10, 2),
Czechia = rnorm(365, 1, 2), check.names = FALSE)
## Calculate Pearson correlation coefficient: ##
corrCoeff <- cor(dt.allData$Austria, dt.allData$DE, method = "pearson", use = "complete.obs")
corrCoeff <- round(corrCoeff, digits = 2)
## Linear regression function extraction by creating linear model: ##
regLine <- lm(DE ~ Austria, data = dt.allData)
## Extract k and d values for the linear function f(x) = kx+d: ##
k <- round(regLine$coef[2], digits = 5)
d <- round(regLine$coef[1], digits = 2)
linRegFunction <- paste0("y = ", d, " + (", k, ")x")
## PLOT: ##
p1 <- ggplot(data = dt.allData, aes(x = Austria, y = DE,
text = paste("Date: ", date, '\n',
"Austria: ", Austria, "MWh/h", '\n',
"DE: ", DE, "\u20ac/MWh"),
group = 1)
) +
geom_point(aes(color = ifelse(date >= now()-weeks(5), "#419F44", "#F07D00"))) +
scale_color_manual(values = c("#F07D00", "#419F44")) +
geom_smooth(method = "lm", se = FALSE, color = "#007d3c") +
annotate("text", x = 10, y = 10,
label = paste("\u03c1 =", corrCoeff, '\n',
linRegFunction), parse = TRUE) +
theme_classic() +
theme(legend.position = "none") +
theme(panel.background = element_blank()) +
xlab("Austria") +
ylab("DE")+
ggtitle("DE vs Austria") +
theme(plot.title = element_text(hjust = 0.5, face = "bold"))
# Correlation plot converting from ggplot to plotly: #
plot <- plotly::ggplotly(p1, tooltip = "text")
这里给出了以下情节:
我用annotate()
来表示相关系数和回归函数。我手动定义 x
和 y
坐标,以便文本输出显示在顶部的中间。由于我有一些这样的数据表 dt.allData
具有不同的轴缩放比例,我想在图中定义文本应始终显示在顶部的中间,具体取决于轴缩放比例而不定义 x
和y
之前手动协调。
首先我会先看看这样的事情是否可以帮助你:
annotate("text",
x = mean(dt.allData$Austria, na.rm = TRUE),
y = max(dt.allData$DE, na.rm = TRUE),
label = paste("\u03c1 =",
corrCoeff, '\n',
linRegFunction),
parse = TRUE,
hjust = .5)
然后,如果您想遍历 x,y
对的列表,您最终会想要转向传递 x
列的函数式编程x1, x2, x3
和 y
列 y1, y2, y3
到 map
函数,然后从每一对中提取相关信息并绘制它们。
我建议使用ggtitle
和hjust = 0.5
:
编辑: 使用 plotly::layout
和 span
标签创建标题:
library(data.table)
library(ggplot2)
library(plotly)
library(lubridate)
dt.allData <- data.table(date = seq(as.Date('2020-01-01'), by = '1 day', length.out = 365),
DE = rnorm(365, 4, 1), Austria = rnorm(365, 10, 2),
Czechia = rnorm(365, 1, 2), check.names = FALSE)
## Calculate Pearson correlation coefficient: ##
corrCoeff <- cor(dt.allData$Austria, dt.allData$DE, method = "pearson", use = "complete.obs")
corrCoeff <- round(corrCoeff, digits = 2)
## Linear regression function extraction by creating linear model: ##
regLine <- lm(DE ~ Austria, data = dt.allData)
## Extract k and d values for the linear function f(x) = kx+d: ##
k <- round(regLine$coef[2], digits = 5)
d <- round(regLine$coef[1], digits = 2)
linRegFunction <- paste0("y = ", d, " + (", k, ")x")
## PLOT: ##
p1 <- ggplot(data = dt.allData, aes(x = Austria, y = DE,
text = paste("Date: ", date, '\n',
"Austria: ", Austria, "MWh/h", '\n',
"DE: ", DE, "\u20ac/MWh"),
group = 1)
) +
geom_point(aes(color = ifelse(date >= now()-weeks(5), "#419F44", "#F07D00"))) +
scale_color_manual(values = c("#F07D00", "#419F44")) +
geom_smooth(method = "lm", formula = 'y ~ x', se = FALSE, color = "#007d3c") +
# ggtitle(label = paste("My pretty useful title", '\n', "\u03c1 =", corrCoeff, '\n', linRegFunction)) +
theme_classic() +
theme(plot.title = element_text(hjust = 0.5)) +
theme(legend.position = "none") +
theme(panel.background = element_blank()) +
xlab("Austria") +
ylab("DE")
# Correlation plot converting from ggplot to plotly: #
# using span tag (directly in control of font-size):
span_plot <- plotly::ggplotly(p1, tooltip = "text") %>% layout(
title = paste(
'<b>My pretty useful title</b>',
'<br><span style="font-size: 15px;">',
'\u03c1 =<i>',
corrCoeff,
'</i><br>',
linRegFunction,
'</span>'
),
margin = list(t = 100)
)
span_plot
编辑: 根据 this answer
添加了 sup
替代方案
# using sup tag:
sup_plot <- plotly::ggplotly(p1, tooltip = "text") %>% layout(
title = paste(
'<b>My pretty useful title</b>',
'<br><sup>',
"\u03c1 =<i>",
corrCoeff,
'</i><br>',
linRegFunction,
'</sup>'
),
margin = list(t = 100)
)
sup_plot
Here你可以在 plotly 文档中找到一些相关信息。
我正在用 ggplot()
绘制散点图,如下所示:
library(data.table)
library(plotly)
library(ggplot2)
library(lubridate)
dt.allData <- data.table(date = seq(as.Date('2020-01-01'), by = '1 day', length.out = 365),
DE = rnorm(365, 4, 1), Austria = rnorm(365, 10, 2),
Czechia = rnorm(365, 1, 2), check.names = FALSE)
## Calculate Pearson correlation coefficient: ##
corrCoeff <- cor(dt.allData$Austria, dt.allData$DE, method = "pearson", use = "complete.obs")
corrCoeff <- round(corrCoeff, digits = 2)
## Linear regression function extraction by creating linear model: ##
regLine <- lm(DE ~ Austria, data = dt.allData)
## Extract k and d values for the linear function f(x) = kx+d: ##
k <- round(regLine$coef[2], digits = 5)
d <- round(regLine$coef[1], digits = 2)
linRegFunction <- paste0("y = ", d, " + (", k, ")x")
## PLOT: ##
p1 <- ggplot(data = dt.allData, aes(x = Austria, y = DE,
text = paste("Date: ", date, '\n',
"Austria: ", Austria, "MWh/h", '\n',
"DE: ", DE, "\u20ac/MWh"),
group = 1)
) +
geom_point(aes(color = ifelse(date >= now()-weeks(5), "#419F44", "#F07D00"))) +
scale_color_manual(values = c("#F07D00", "#419F44")) +
geom_smooth(method = "lm", se = FALSE, color = "#007d3c") +
annotate("text", x = 10, y = 10,
label = paste("\u03c1 =", corrCoeff, '\n',
linRegFunction), parse = TRUE) +
theme_classic() +
theme(legend.position = "none") +
theme(panel.background = element_blank()) +
xlab("Austria") +
ylab("DE")+
ggtitle("DE vs Austria") +
theme(plot.title = element_text(hjust = 0.5, face = "bold"))
# Correlation plot converting from ggplot to plotly: #
plot <- plotly::ggplotly(p1, tooltip = "text")
这里给出了以下情节:
我用annotate()
来表示相关系数和回归函数。我手动定义 x
和 y
坐标,以便文本输出显示在顶部的中间。由于我有一些这样的数据表 dt.allData
具有不同的轴缩放比例,我想在图中定义文本应始终显示在顶部的中间,具体取决于轴缩放比例而不定义 x
和y
之前手动协调。
首先我会先看看这样的事情是否可以帮助你:
annotate("text",
x = mean(dt.allData$Austria, na.rm = TRUE),
y = max(dt.allData$DE, na.rm = TRUE),
label = paste("\u03c1 =",
corrCoeff, '\n',
linRegFunction),
parse = TRUE,
hjust = .5)
然后,如果您想遍历 x,y
对的列表,您最终会想要转向传递 x
列的函数式编程x1, x2, x3
和 y
列 y1, y2, y3
到 map
函数,然后从每一对中提取相关信息并绘制它们。
我建议使用ggtitle
和hjust = 0.5
:
编辑: 使用 plotly::layout
和 span
标签创建标题:
library(data.table)
library(ggplot2)
library(plotly)
library(lubridate)
dt.allData <- data.table(date = seq(as.Date('2020-01-01'), by = '1 day', length.out = 365),
DE = rnorm(365, 4, 1), Austria = rnorm(365, 10, 2),
Czechia = rnorm(365, 1, 2), check.names = FALSE)
## Calculate Pearson correlation coefficient: ##
corrCoeff <- cor(dt.allData$Austria, dt.allData$DE, method = "pearson", use = "complete.obs")
corrCoeff <- round(corrCoeff, digits = 2)
## Linear regression function extraction by creating linear model: ##
regLine <- lm(DE ~ Austria, data = dt.allData)
## Extract k and d values for the linear function f(x) = kx+d: ##
k <- round(regLine$coef[2], digits = 5)
d <- round(regLine$coef[1], digits = 2)
linRegFunction <- paste0("y = ", d, " + (", k, ")x")
## PLOT: ##
p1 <- ggplot(data = dt.allData, aes(x = Austria, y = DE,
text = paste("Date: ", date, '\n',
"Austria: ", Austria, "MWh/h", '\n',
"DE: ", DE, "\u20ac/MWh"),
group = 1)
) +
geom_point(aes(color = ifelse(date >= now()-weeks(5), "#419F44", "#F07D00"))) +
scale_color_manual(values = c("#F07D00", "#419F44")) +
geom_smooth(method = "lm", formula = 'y ~ x', se = FALSE, color = "#007d3c") +
# ggtitle(label = paste("My pretty useful title", '\n', "\u03c1 =", corrCoeff, '\n', linRegFunction)) +
theme_classic() +
theme(plot.title = element_text(hjust = 0.5)) +
theme(legend.position = "none") +
theme(panel.background = element_blank()) +
xlab("Austria") +
ylab("DE")
# Correlation plot converting from ggplot to plotly: #
# using span tag (directly in control of font-size):
span_plot <- plotly::ggplotly(p1, tooltip = "text") %>% layout(
title = paste(
'<b>My pretty useful title</b>',
'<br><span style="font-size: 15px;">',
'\u03c1 =<i>',
corrCoeff,
'</i><br>',
linRegFunction,
'</span>'
),
margin = list(t = 100)
)
span_plot
编辑: 根据 this answer
添加了sup
替代方案
# using sup tag:
sup_plot <- plotly::ggplotly(p1, tooltip = "text") %>% layout(
title = paste(
'<b>My pretty useful title</b>',
'<br><sup>',
"\u03c1 =<i>",
corrCoeff,
'</i><br>',
linRegFunction,
'</sup>'
),
margin = list(t = 100)
)
sup_plot
Here你可以在 plotly 文档中找到一些相关信息。