如果我的函数来自另一个 .c,我可以知道调用我的函数的文件名和函数名吗?
Can I know the file and function names from where my function is called if it's from another .c?
我正在开发一个库,我想知道有关我提供的其中一个函数的调用者的一些数据。特别是,我需要知道调用我的函数(重新定义的 malloc)的文件名、函数名和行。
编辑:这是一个最小的工作示例,我可以在其中检测用户何时调用 malloc 并将他“重定向”到我自己的 malloc 函数:
main.c:
#include <stdio.h>
#include <stdlib.h>
#include "myLib.h"
int main(){
printf("Inside main, asking for memory\n");
int *p = malloc(sizeof(int));
*p = 3;
free(p);
return 0;
}
myLib.c:
#include "myLib.h"
void * myAlloc (size_t size){
void * p = NULL;
fprintf(stderr, "Inside my own malloc\n");
p = (malloc)(size);
return p;
}
#undef malloc
#define malloc(size) myAlloc(size)
myLib.h:
#ifndef MYLIB_H
#define MYLIB_H
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#define malloc(size) myAlloc(size)
void * myAlloc(size_t size);
#endif
我试过使用 _FILE_ _func_ 和 _LINE_关键字,但我无法让它工作,因为它在不同的模块中。
你可以:
//mylib.h
#ifndef MYLIB_H
#define MYLIB_H
#include <stdlib.h>
// replace malloc in case it's already a macro
#ifdef malloc
#undef malloc
#endif
// I believe that from the standards point of view, this is undefined behavior
#define malloc(size) my_alloc(size, __FILE__, __LINE__, __func__)
#ifdef __GNUC__
// Allow compiler to do static checking.
__attribute__((__alloc_size__(1), __malloc__))
#endif
void *my_alloc(size_t size, const char *file, int line, const char *func);
// ^^^^^^^^ I do not like camelCase case - one snake case to rule them all.
#endif
// mylib.c
#include "mylib.h" // do not ever mix uppercase and lowercase in filenames
#undef malloc // undef malloc so we don't call ourselves recursively
#include <stdio.h>
void *my_alloc(size_t size, const char *file, int line, const char *func){
fprintf(stderr, "Och my god, you wouldn't believe it!\n"
"A function %s in file %s at line %d called malloc!\n",
func, file, line);
return malloc(size);
}
您可能还会看到如何 assert does it. If you are aiming at glibc, read glibc docs replacing malloc。
正如您发现的那样,用户可能会执行 (malloc)(size)
cicumvent 宏扩展。你可以这样做:
void *my_alloc(size_t size, const char *file, int line, const char *func);
static inline void *MY_ALLOC(size_t size) {
return my_alloc(size, NULL, 0, NULL);
}
#define MY_ALLOC(size) my_alloc(size, __FILE__, __LINE__, __func__)
// if called with `malloc()` then MY_ALLOC is expanded
// if called as `(malloc)`, then just expands to MY_ALLOC.
#define malloc MY_ALLOC
int main() {
malloc(10); // calls my_alloc(10, "main.c", 62, "main");
(malloc)(20); // calls my_alloc(20, NULL, 0, NULL);
}
GLIBC 为 malloc()、free()...定义了隐藏符号,它们被称为 __libc_malloc()、__libc_free()...
因此,您可以极大地简化调试宏。
在m.h中,只需定义如下:
#if DEBUG_LEVEL > 0
extern void *__libc_malloc (size_t bytes);
extern void *myMalloc(size_t size, const char *filename, const char *funcname, int line);
#define malloc(size) myMalloc(size, __FILE__, __FUNCTION__, __LINE__)
#endif
然后你可以写一个程序定义myMalloc()如下(例如文件名是m.c):
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include "m.h"
#if DEBUG_LEVEL > 0
void *myMalloc(
size_t size,
const char *filename,
const char *funcname,
int line
) {
fprintf(stderr, "malloc(%zu) called from %s/%s()#%d\n", size, filename, funcname, line);
return __libc_malloc(size);
}
#endif
char *dup_str(char *string) {
char *str = malloc(strlen(string) + 1);
strcpy(str, string);
return str;
}
int main(int ac, char *av[]) {
char *str;
if (av[1]) {
str = dup_str(av[1]);
} else {
str = dup_str("NULL");
}
printf("String = '%s'\n", str);
free(str);
return 0;
}
当您在非调试模式下编译此示例程序时:
$ gcc m.c -DDEBUG_LEVEL=0
$ ./a.out azerty
String = 'azerty'
当您在调试模式下编译程序时:
$ gcc m.c -DDEBUG_LEVEL=1
$ ./a.out azerty
malloc(7) called from m.c/dup_str()#27
String = 'azerty'
我正在开发一个库,我想知道有关我提供的其中一个函数的调用者的一些数据。特别是,我需要知道调用我的函数(重新定义的 malloc)的文件名、函数名和行。
编辑:这是一个最小的工作示例,我可以在其中检测用户何时调用 malloc 并将他“重定向”到我自己的 malloc 函数:
main.c:
#include <stdio.h>
#include <stdlib.h>
#include "myLib.h"
int main(){
printf("Inside main, asking for memory\n");
int *p = malloc(sizeof(int));
*p = 3;
free(p);
return 0;
}
myLib.c:
#include "myLib.h"
void * myAlloc (size_t size){
void * p = NULL;
fprintf(stderr, "Inside my own malloc\n");
p = (malloc)(size);
return p;
}
#undef malloc
#define malloc(size) myAlloc(size)
myLib.h:
#ifndef MYLIB_H
#define MYLIB_H
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#define malloc(size) myAlloc(size)
void * myAlloc(size_t size);
#endif
我试过使用 _FILE_ _func_ 和 _LINE_关键字,但我无法让它工作,因为它在不同的模块中。
你可以:
//mylib.h
#ifndef MYLIB_H
#define MYLIB_H
#include <stdlib.h>
// replace malloc in case it's already a macro
#ifdef malloc
#undef malloc
#endif
// I believe that from the standards point of view, this is undefined behavior
#define malloc(size) my_alloc(size, __FILE__, __LINE__, __func__)
#ifdef __GNUC__
// Allow compiler to do static checking.
__attribute__((__alloc_size__(1), __malloc__))
#endif
void *my_alloc(size_t size, const char *file, int line, const char *func);
// ^^^^^^^^ I do not like camelCase case - one snake case to rule them all.
#endif
// mylib.c
#include "mylib.h" // do not ever mix uppercase and lowercase in filenames
#undef malloc // undef malloc so we don't call ourselves recursively
#include <stdio.h>
void *my_alloc(size_t size, const char *file, int line, const char *func){
fprintf(stderr, "Och my god, you wouldn't believe it!\n"
"A function %s in file %s at line %d called malloc!\n",
func, file, line);
return malloc(size);
}
您可能还会看到如何 assert does it. If you are aiming at glibc, read glibc docs replacing malloc。
正如您发现的那样,用户可能会执行 (malloc)(size)
cicumvent 宏扩展。你可以这样做:
void *my_alloc(size_t size, const char *file, int line, const char *func);
static inline void *MY_ALLOC(size_t size) {
return my_alloc(size, NULL, 0, NULL);
}
#define MY_ALLOC(size) my_alloc(size, __FILE__, __LINE__, __func__)
// if called with `malloc()` then MY_ALLOC is expanded
// if called as `(malloc)`, then just expands to MY_ALLOC.
#define malloc MY_ALLOC
int main() {
malloc(10); // calls my_alloc(10, "main.c", 62, "main");
(malloc)(20); // calls my_alloc(20, NULL, 0, NULL);
}
GLIBC 为 malloc()、free()...定义了隐藏符号,它们被称为 __libc_malloc()、__libc_free()...
因此,您可以极大地简化调试宏。
在m.h中,只需定义如下:
#if DEBUG_LEVEL > 0
extern void *__libc_malloc (size_t bytes);
extern void *myMalloc(size_t size, const char *filename, const char *funcname, int line);
#define malloc(size) myMalloc(size, __FILE__, __FUNCTION__, __LINE__)
#endif
然后你可以写一个程序定义myMalloc()如下(例如文件名是m.c):
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include "m.h"
#if DEBUG_LEVEL > 0
void *myMalloc(
size_t size,
const char *filename,
const char *funcname,
int line
) {
fprintf(stderr, "malloc(%zu) called from %s/%s()#%d\n", size, filename, funcname, line);
return __libc_malloc(size);
}
#endif
char *dup_str(char *string) {
char *str = malloc(strlen(string) + 1);
strcpy(str, string);
return str;
}
int main(int ac, char *av[]) {
char *str;
if (av[1]) {
str = dup_str(av[1]);
} else {
str = dup_str("NULL");
}
printf("String = '%s'\n", str);
free(str);
return 0;
}
当您在非调试模式下编译此示例程序时:
$ gcc m.c -DDEBUG_LEVEL=0
$ ./a.out azerty
String = 'azerty'
当您在调试模式下编译程序时:
$ gcc m.c -DDEBUG_LEVEL=1
$ ./a.out azerty
malloc(7) called from m.c/dup_str()#27
String = 'azerty'