如何把一个RestTemplate放到一个单独的class中?

How to put a RestTemplate into a separate class?

我有一个 Spring 应用程序,其 RestTemplate 的定义如下:

@SpringBootApplication(scanBasePackages = {"com.mycompany"})
public class MyApplication extends SpringBootServletInitializer {

[...]
  @Bean
  public RestTemplate getRestTemplate1() {
    return new RestTemplate();
  }

  @Bean("restTemplate2")
  public RestTemplate getRestTemplate2() throws KeyStoreException, NoSuchAlgorithmException, KeyManagementException {
    [...]
  }

[...]

}

我想把getRestTemplate2放到一个单独的class中。所以我创建了以下 class:

@Configuration
@ComponentScan
public class GetRestTemplate2 {
    @Bean("restTemplate2")
    public RestTemplate getRestTemplate2() throws KeyStoreException, NoSuchAlgorithmException, KeyManagementException {
      [...]
    }

}

当我启动应用程序时收到错误消息

org.springframework.beans.factory.support.BeanDefinitionOverrideException: Invalid bean definition with name 'restTemplate2' 
defined in class path resource [XXXXXXXX.class]: Cannot register bean definition 
[Root bean: class [null]; scope=; abstract=false; lazyInit=null; autowireMode=3; dependencyCheck=0; autowireCandidate=true; primary=false; 
factoryBeanName=restTemplate2; factoryMethodName=getRestTemplate2; initMethodName=null; destroyMethodName=(inferred); defined 
in class path resource [XXXXXXXXX.class]] for bean 'restTemplate2': 
There is already [Generic bean: class [XXXXXXXXX]; scope=singleton; abstract=false; 
lazyInit=null; autowireMode=0; dependencyCheck=0; autowireCandidate=true; primary=false; factoryBeanName=null; factoryMethodName=null; 
initMethodName=null; destroyMethodName=null; defined in file 
[XXXXXXXX.class]] bound.

如何确保创建 restTemplate2 的代码位于单独的 class 中并被 Spring 正确检测到?

更新 1:GetRestTemplate2 class 重命名为 GetRestTemplate2Config 没有帮助。

这似乎有效:

@Configuration
@ComponentScan
public class GetRestTemplate2Config {

    @Bean(name = "restTemplate2")
    public RestTemplate getRestTemplate2() throws KeyStoreException, 
        NoSuchAlgorithmException, KeyManagementException {
       [...]
    }
}