结合处理不同类型的发布者
Combine handle different type of publishers
我是 Combine 的新手,一直被这个问题困扰。我有基本的注册表,如果一切正常,return 的空响应为 200 代码,如果表单有一些注册失败,则为 442。
这是可以处理空响应并且工作正常的代码
extension Route where ResultType: EmptyResult {
func emptyResult() -> AnyPublisher<Void, APIError> {
return URLSession.shared.dataTaskPublisher(for: urlRequest)
.print("EMPTY RESULT")
.tryMap { data, response in
guard let httpResponse = response as? HTTPURLResponse else { throw APIError.nonHttpResponse(description: "Not http resp") }
let statusCode = httpResponse.statusCode
guard (200..<300).contains(statusCode) else { throw APIError.nonHttpResponse(description: "bad response")
}
return Void()
}.mapError { error in
print("Error \(error)")
return .network(description: error.localizedDescription)
}
.eraseToAnyPublisher()
}
}
但是,我如何才能 return 使用其他类型的发布者?例如
struct CustomError: Decodable {
let usernameError: String
let emailError: String
}
我的网络电话:
API.registration(name: name, email: email, password: password, schoolID: selectedSchool?.id ?? 0)
.print("Registration")
.receive(on: DispatchQueue.main)
.sink(receiveCompletion: { (completion) in
switch completion {
case let .failure(error):
print("ERROR \(error)")
case .finished: break
}
}, receiveValue: { value in
print(value)
})
.store(in: &disposables)
所以你有一个网络请求,如果请求成功,returns 一个 200 响应和一个空主体,而如果出现表单错误,它 returns 一个特定的状态代码和响应中的错误。
我建议将 Publisher
的 Output
类型保留为 Void
,但是,如果出现格式错误,请解码错误并将其作为 Void
的一部分抛出=15=].
struct LoginError: Decodable {
let usernameError: String
let emailError: String
}
enum APIError: Error {
case failureStatus(code: Int)
case login(LoginError)
case nonHttpResponse(description: String)
case network(Error)
}
func emptyResult() -> AnyPublisher<Void, APIError> {
return URLSession.shared.dataTaskPublisher(for: urlRequest)
.print("EMPTY RESULT")
.tryMap { data, response in
guard let httpResponse = response as? HTTPURLResponse else { throw APIError.nonHttpResponse(description: "Not http response") }
let statusCode = httpResponse.statusCode
guard (200..<300).contains(statusCode) else {
if statusCode == 442 {
let loginError = try JSONDecoder().decode(LoginError.self, from: data)
throw APIError.login(loginError)
} else {
throw APIError.failureStatus(code: statusCode)
}
}
return Void()
}.mapError { error in
switch error {
case let apiError as APIError:
return apiError
default:
return .network(error)
}
}
.eraseToAnyPublisher()
}
然后您可以通过 switch
处理 sink
中的 error
来处理特定错误:
API.registration(name: name, email: email, password: password, schoolID: selectedSchool?.id ?? 0)
.print("Registration")
.receive(on: DispatchQueue.main)
.sink(receiveCompletion: { (completion) in
switch completion {
case let .failure(error):
switch error {
case .login(let loginError):
print("Login failed, \(loginError.emailError), \(loginError.usernameError)")
default:
print(error)
}
case .finished: break
}
}, receiveValue: { value in
print(value)
})
.store(in: &disposables)
我是 Combine 的新手,一直被这个问题困扰。我有基本的注册表,如果一切正常,return 的空响应为 200 代码,如果表单有一些注册失败,则为 442。
这是可以处理空响应并且工作正常的代码
extension Route where ResultType: EmptyResult {
func emptyResult() -> AnyPublisher<Void, APIError> {
return URLSession.shared.dataTaskPublisher(for: urlRequest)
.print("EMPTY RESULT")
.tryMap { data, response in
guard let httpResponse = response as? HTTPURLResponse else { throw APIError.nonHttpResponse(description: "Not http resp") }
let statusCode = httpResponse.statusCode
guard (200..<300).contains(statusCode) else { throw APIError.nonHttpResponse(description: "bad response")
}
return Void()
}.mapError { error in
print("Error \(error)")
return .network(description: error.localizedDescription)
}
.eraseToAnyPublisher()
}
}
但是,我如何才能 return 使用其他类型的发布者?例如
struct CustomError: Decodable {
let usernameError: String
let emailError: String
}
我的网络电话:
API.registration(name: name, email: email, password: password, schoolID: selectedSchool?.id ?? 0)
.print("Registration")
.receive(on: DispatchQueue.main)
.sink(receiveCompletion: { (completion) in
switch completion {
case let .failure(error):
print("ERROR \(error)")
case .finished: break
}
}, receiveValue: { value in
print(value)
})
.store(in: &disposables)
所以你有一个网络请求,如果请求成功,returns 一个 200 响应和一个空主体,而如果出现表单错误,它 returns 一个特定的状态代码和响应中的错误。
我建议将 Publisher
的 Output
类型保留为 Void
,但是,如果出现格式错误,请解码错误并将其作为 Void
的一部分抛出=15=].
struct LoginError: Decodable {
let usernameError: String
let emailError: String
}
enum APIError: Error {
case failureStatus(code: Int)
case login(LoginError)
case nonHttpResponse(description: String)
case network(Error)
}
func emptyResult() -> AnyPublisher<Void, APIError> {
return URLSession.shared.dataTaskPublisher(for: urlRequest)
.print("EMPTY RESULT")
.tryMap { data, response in
guard let httpResponse = response as? HTTPURLResponse else { throw APIError.nonHttpResponse(description: "Not http response") }
let statusCode = httpResponse.statusCode
guard (200..<300).contains(statusCode) else {
if statusCode == 442 {
let loginError = try JSONDecoder().decode(LoginError.self, from: data)
throw APIError.login(loginError)
} else {
throw APIError.failureStatus(code: statusCode)
}
}
return Void()
}.mapError { error in
switch error {
case let apiError as APIError:
return apiError
default:
return .network(error)
}
}
.eraseToAnyPublisher()
}
然后您可以通过 switch
处理 sink
中的 error
来处理特定错误:
API.registration(name: name, email: email, password: password, schoolID: selectedSchool?.id ?? 0)
.print("Registration")
.receive(on: DispatchQueue.main)
.sink(receiveCompletion: { (completion) in
switch completion {
case let .failure(error):
switch error {
case .login(let loginError):
print("Login failed, \(loginError.emailError), \(loginError.usernameError)")
default:
print(error)
}
case .finished: break
}
}, receiveValue: { value in
print(value)
})
.store(in: &disposables)