如何将这个 .plist 文件直接解析为 Swift 中的对象？

Question

我有一个如下所示的 covid.plist 文件，并试图弄清楚如何解析对象并读取此数据？

covid.plist

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
    <key>key1</key>
    <string>value for key1</string>
    <key> key2</key>
    <string>valua for key1</string>
    <key>Covid1</key>
    <dict>
        <key>covid1_key</key>
        <string>covid1_value</string>
    </dict>
    <key>Covid2</key>
    <dict>
        <key>covid2_key</key>
        <string>covid2_value</string>
    </dict>
</dict>
</plist>

Answer 1

你的代码似乎被感染了所以我戴上口罩，洗手并保持我的 mac 小距离 :) 无论如何我认为 PropertyListDecoder 可以用来直接解码 plist 文件到你的对象针对您的情况

struct Covid1:Codable {
    var covid1_key:String?
    private enum CodingKeys : String, CodingKey {
              case covid2_key = "covid1_key"
    }
}

struct Covid2:Codable {
    var covid2_key:String?
    private enum CodingKeys : String, CodingKey {
              case covid2_key = "covid2_key"
    }    
}

struct PlistConfiguration:Codable {
    var key1:String?
    var covid1: Covid1?
    var covid2: Covid2?
    
    private enum CodingKeys : String, CodingKey {
              case key1 = "key1"
              case covid1 = "Covid1"
              case covid2 = "Covid2"
    }
}

并使用此功能进行操作：

func parseCovid() -> PlistConfiguration {
    let url = Bundle.main.url(forResource: "covid", withExtension: "plist")!
    let data = try! Data(contentsOf: url)
    let decoder = PropertyListDecoder()
    return try! decoder.decode(PlistConfiguration.self, from: data)
}

如何将这个 .plist 文件直接解析为 Swift 中的对象？

How can I parse this .plist file directly to the objects in Swift?

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