Python : 获取多张图片的特征
Python : Get features of several images
我想获得位于同一文件夹中的多个图像的功能。
我的代码如下 - 先决条件（需要库）：
import numpy as np
from PIL import Image
import glob
import cv2
import os
图像所在文件夹的定义（约6000张）
images_dir = "TrainImages"
创建定义不同变量并计算它们的函数
def get_data_from_image(image_path):
cv_img = cv2.imread(image_path)
(means, stds) = cv2.meanStdDev(cv_img)
stats = np.concatenate([means, stds]).flatten()
image_features_list = [stats.tolist()]
return image_features_list
创建扫描和分析图像的变量
image_files = [x.path for x in os.scandir(images_dir)]
循环函数的创建
i = 0
mylist =[]
for i in range (4): # I test only 4 images, could be more
mylist.append((get_data_from_image(image_files[i])))
运行 东西
image_features_list = get_data_from_image(image_files[i])
查看输出
image_features_list
输出提供仅一张图像的特征，而不是文件夹
中的所有图像
[出局]:
[[114.31548828125001,
139.148388671875,
139.57832682291667,
50.54138521536725,
53.82290182999255,
51.946187641459595]]
如果我能有一个关于如何拥有所有图像（不仅仅是一个）的特征的解决方案，我将不胜感激。鉴于此，请毫不犹豫地更正代码。
谢谢和最诚挚的问候
在友好人士的一些评论之后，这里有一个附加信息供那些对响应感兴趣的人使用：要查看的输出是 mylist。
mylist
[出局]:
[[[144.28788548752834,
151.28145691609978,
148.6195351473923,
51.50620316379085,
53.36979275398226,
52.2493589172815]],
[[56.220865079365076,
59.99653968253968,
60.28386507936508,
66.72797279655177,
65.24673515467009,
64.93141350917332]],
[[125.2066064453125,
118.1168994140625,
145.0827685546875,
68.95463582009148,
52.65138276425348,
56.68269683130363]],
[[114.31548828125001,
139.148388671875,
139.57832682291667,
50.54138521536725,
53.82290182999255,
51.946187641459595]]]
感谢您的帮助。这是一个很棒的论坛！
试试这个方法并告诉我它是否成功
import os, os.path
import numpy as np
from PIL import Image
import cv2
def get_data_from_image(image_path):
cv_img = cv2.imread(image_path)
(means, stds) = cv2.meanStdDev(cv_img)
stats = np.concatenate([means, stds]).flatten()
image_features_list = [stats.tolist()]
return image_features_list
images_dir = 'C:\Users\User\Directory\TrainImages\'
images_names = []
with os.scandir(images_dir) as dirs:
for entry in dirs:
images_names.append(entry.name)
for image in images_names:
path = images_dir + image
image_features_list = get_data_from_image(path))
print(image_features_list)
我想获得位于同一文件夹中的多个图像的功能。
我的代码如下 - 先决条件（需要库）：
import numpy as np
from PIL import Image
import glob
import cv2
import os
图像所在文件夹的定义（约6000张）
images_dir = "TrainImages"
创建定义不同变量并计算它们的函数
def get_data_from_image(image_path):
cv_img = cv2.imread(image_path)
(means, stds) = cv2.meanStdDev(cv_img)
stats = np.concatenate([means, stds]).flatten()
image_features_list = [stats.tolist()]
return image_features_list
创建扫描和分析图像的变量
image_files = [x.path for x in os.scandir(images_dir)]
循环函数的创建
i = 0
mylist =[]
for i in range (4): # I test only 4 images, could be more
mylist.append((get_data_from_image(image_files[i])))
运行 东西
image_features_list = get_data_from_image(image_files[i])
查看输出
image_features_list
输出提供仅一张图像的特征，而不是文件夹
中的所有图像[出局]:
[[114.31548828125001, 139.148388671875, 139.57832682291667, 50.54138521536725, 53.82290182999255, 51.946187641459595]]
如果我能有一个关于如何拥有所有图像（不仅仅是一个）的特征的解决方案，我将不胜感激。鉴于此，请毫不犹豫地更正代码。 谢谢和最诚挚的问候
在友好人士的一些评论之后，这里有一个附加信息供那些对响应感兴趣的人使用：要查看的输出是 mylist。
mylist
[出局]:
[[[144.28788548752834, 151.28145691609978, 148.6195351473923, 51.50620316379085, 53.36979275398226, 52.2493589172815]], [[56.220865079365076, 59.99653968253968, 60.28386507936508, 66.72797279655177, 65.24673515467009, 64.93141350917332]], [[125.2066064453125, 118.1168994140625, 145.0827685546875, 68.95463582009148, 52.65138276425348, 56.68269683130363]], [[114.31548828125001, 139.148388671875, 139.57832682291667, 50.54138521536725, 53.82290182999255, 51.946187641459595]]]
感谢您的帮助。这是一个很棒的论坛！
试试这个方法并告诉我它是否成功
import os, os.path
import numpy as np
from PIL import Image
import cv2
def get_data_from_image(image_path):
cv_img = cv2.imread(image_path)
(means, stds) = cv2.meanStdDev(cv_img)
stats = np.concatenate([means, stds]).flatten()
image_features_list = [stats.tolist()]
return image_features_list
images_dir = 'C:\Users\User\Directory\TrainImages\'
images_names = []
with os.scandir(images_dir) as dirs:
for entry in dirs:
images_names.append(entry.name)
for image in images_names:
path = images_dir + image
image_features_list = get_data_from_image(path))
print(image_features_list)