React Native Navigation：检查抽屉是否打开

Question

我有一个组件位于 Drawer 标签之外，但它位于 NavigationContainer 内。所以我使用 useRef 从反应中获取 navigate 方法。

所以我用这个例子：Navigating without navigation prop

但是现在，我无法获取抽屉的状态（是打开还是关闭）。

这是我的 App 组件：

import 'react-native-gesture-handler';
import React from 'react';
import { createStore, applyMiddleware } from "redux";
import thunk from "redux-thunk";
import { Provider } from "react-redux";
import GetInformationByLocation from "./reducers/GetInformationByLocation";
import Wrapper from './components/Wrapper';
import { createDrawerNavigator } from '@react-navigation/drawer';
import { NavigationContainer } from '@react-navigation/native';
import GeoDisplay from "./components/GeoDisplay";
import { Text } from "react-native";
import { navigationRef } from "./helpers/Navigator";

const store = createStore(GetInformationByLocation, applyMiddleware(thunk));
/*
 * TODO:
 * 1. Wrap everything with parent component
 * 2. Search bar
 * 3. Save searched cities.
 * 4. Check if the city is undefined and suggest nearest city.
 * 5. Animated background
 * 6. Fancy and animated font
 * 7. Setup menu преди показване на приложението
 */

const Drawer = createDrawerNavigator();

const App = () => {
    return (
        <Provider store={store}>
            <NavigationContainer ref={navigationRef}>
                <Wrapper />
                <Drawer.Navigator initialRouteName="Home">
                    <Drawer.Screen name="Home" component={GeoDisplay} />
                </Drawer.Navigator>
            </NavigationContainer>
        </Provider >
    );
}


export default App;

和我的 Wrapper.js 组件：

import React, { useEffect, useState } from 'react';
import { StyleSheet, View, StatusBar } from 'react-native';
import { SearchBar, Header } from 'react-native-elements';
import { MainUI } from '../styling/UI';
import * as Navigator from "../helpers/Navigator";
import { DrawerActions } from "@react-navigation/native";

const Wrapper = (props) => {

    const [search, setSearch] = useState(true);

    const openDrawer = () => {
        Navigator.navigationRef.current.dispatch(DrawerActions.openDrawer())
        setSearch(false);
    }


    useEffect(() => {
    }, []);

    return (
        <>
            <StatusBar backgroundColor={"#011E25"} />
            <Header
                leftComponent={{ icon: 'menu', color: '#fff', onPress: () => { openDrawer() } }}
                centerComponent={{ text: 'COVID Bulgaria', style: { color: '#fff' } }}
                rightComponent={{ icon: 'home', color: '#fff' }}
                backgroundColor={'#011E25'}
            />
            {search &&
                <View>
                    <SearchBar placeholder="Търси град" containerStyle={MainUI.searchContainer} />
                </View>
            }
        </>
    )

}

export default Wrapper;

我使用 navigationRef 调度 openDrawer() 操作 Navigator.navigationRef.current.dispatch(DrawerActions.openDrawer()) 但无法获取抽屉的状态。

试了很多方法都不行。

提前致谢。

Answer 1

您可以创建一个助手 class，例如：

class DrawerHandler() {
 
 openDrawer() {
     this.drawerOpened = true;  
 }

closeDrawer() {
     this.drawerOpened = false;    
 }

getDrawerStatus() {
  return this.drawerOpened;
 }
}

export default new DrawerHandler();

在抽屉打开和关闭时使用打开和关闭函数并获取抽屉状态的函数

Answer 2

您可以通过获取导航状态来检查抽屉是否打开：

const state = navigationRef.current.getRootState();
const isDrawerOpen = state.history.some((it) => it.type === 'drawer');

以上代码假定抽屉位于根目录下。如果它是嵌套的，则需要遍历状态以找到具有 type: 'drawer'.

的状态对象

不清楚为什么要从问题上查。通常你不需要检查它。如果你在抽屉已经打开的情况下调度 DrawerActions.openDrawer()，什么都不会发生。所以检查是不必要的。如果你想在抽屉打开时关闭抽屉，你可以改为调度 DrawerActions.toggleDrawer()。

React Native Navigation：检查抽屉是否打开

React Native Navigation: Check if drawer is opened or not

reactjs

react-native

react-navigation-drawer

react-navigation-v5