将原型成员序列化或编码为字节数组

Question

我有这样的原型成员

String = "1324211127562612736"
Varint = 1
Varint = 10000000000

我如何序列化为结果应如下所示的字节数组？

0x0a, 0x13, 0x31, 0x33, 0x32, 0x34, 0x32, 0x31, 0x31, 0x31, 0x32, 0x37, 0x35, 0x36, 0x32, 0x36, 0x31, 0x32, 0x37, 0x33, 0x36, 0x20, 0x01, 0x28, 0x80, 0xc8, 0xaf, 0xa0, 0x25

Answer 1

通过运行十六进制 0A133133323432313131323735363236313237333620012880C8AFA025 到 https://protogen.marcgravell.com/decode，我们可以看到我们有：

Field #1: 0A String Length = 19, Hex = 13, UTF8 = "1324211127562612 ..." (total 19 chars)
Field #4: 20 Varint Value = 1, Hex = 01
Field #5: 28 Varint Value = 10000000000, Hex = 80-C8-AF-A0-25

告诉我们字段编号；所以，让我们试试：

[ProtoContract]
class Foo
{
    [ProtoMember(1)]
    public string X { get; set; }

    [ProtoMember(4)]
    public int Y { get; set; }

    [ProtoMember(5)]
    public long Z { get; set; }
}

我们可以通过序列化生成有效载荷：

var foo = new Foo { X = "1324211127562612736", Y = 1, Z = 10000000000 };
using var ms = new MemoryStream();
Serializer.Serialize(ms, foo);
if (!ms.TryGetBuffer(out var buffer))
{   // in reality we should never hit this - TryGetBuffer should work
    buffer = new ArraySegment<byte>(ms.ToArray());
}
Console.WriteLine(BitConverter.ToString(buffer.Array, buffer.Offset, buffer.Count));

输出：

0A-13-31-33-32-34-32-31-31-31-32-37-35-36-32-36-31-32-37-33-36-20-01-28-80-C8-AF-A0-25

将原型成员序列化或编码为字节数组

Serialize or encode proto member to byte array

c#

protobuf-net