python中设置交集方法的使用方法
How to use the set intersection method in python
at_set = {'Num1', 'Num2', 'Num3'}
for files in os.listdir(zipped_trots_files):
zipped_path = os.path.join(zipped_trots_files, files)
with open(zipped_path, 'r') as output:
reader = csv.reader(output, delimiter = '\t')
for row in reader:
read = [row for row in reader if row]
for row in read:
if set(row).intersection(at_set):
print(row)
我猜我用错了交集函数...有人能看到吗?我试图只打印包含 Num1
、Num2
或 Num3
的行
当我这样做时 print
我什么也没收到...
有重复的迭代。您需要删除过多的迭代或通过调用 output.seek(0)
.
返回到 reader
的开头
at_set = {'Num1', 'Num2', 'Num3'}
for files in os.listdir(zipped_trots_files):
zipped_path = os.path.join(zipped_trots_files, files)
with open(zipped_path, 'r') as output:
reader = csv.reader(output, delimiter = '\t')
for row in reader:
if row and set(row).intersection(at_set):
print(row)
at_set = {'Num1', 'Num2', 'Num3'}
for files in os.listdir(zipped_trots_files):
zipped_path = os.path.join(zipped_trots_files, files)
with open(zipped_path, 'r') as output:
reader = csv.reader(output, delimiter = '\t')
for row in reader:
read = [row for row in reader if row]
for row in read:
if set(row).intersection(at_set):
print(row)
我猜我用错了交集函数...有人能看到吗?我试图只打印包含 Num1
、Num2
或 Num3
当我这样做时 print
我什么也没收到...
有重复的迭代。您需要删除过多的迭代或通过调用 output.seek(0)
.
reader
的开头
at_set = {'Num1', 'Num2', 'Num3'}
for files in os.listdir(zipped_trots_files):
zipped_path = os.path.join(zipped_trots_files, files)
with open(zipped_path, 'r') as output:
reader = csv.reader(output, delimiter = '\t')
for row in reader:
if row and set(row).intersection(at_set):
print(row)