如何在 `react-hook-form` 库中将 Yup 验证模式与 Controller 组件一起使用

Question

我们有一个想要使用的第 3 方组件SecondaryInput
想使用 Yup 验证（不知道如何在 Controller 组件中将 yup 与规则道具一起使用）
受控组件在子组件内部，所以我使用的是 useFormContext
架构代码不工作

我的代码是这样的

注意：我不能在自定义组件中使用 ref，因为它不使用像 ref

这样的道具

父组件

  const schema = yup.object().shape({
    patientIdentity: yup.object().shape({
      firstName: yup.string().required('Required field'),
      lastName: yup.string().required('Required field'),
    }),
  });
  const methods = useForm();
  const {
    errors,
    handleSubmit,
    register,
    setValue,
    reset,
    getValues,
  } = useForm({
    defaultValues: {
      patientIdentity: {
        firstName: 'test 1',
        lastName: 'Test 2',
      },
    },
    validationSchema: schema,
  });

  const onSubmit = (data, e) => {
    console.log('onSubmit');
    console.log(data, e);
  };

  const onError = (errors, e) => {
    console.log('onError');
    console.log(errors, e);
  };
  console.log('errors', errors); // Not able to see any any error 
  console.log('getValues:> ', getValues()); Not able to see any any values
  return (
    <View style={[t.flex1]}>
      {/* Removed code from here */}
      <View style={[t.flex1, t.selfCenter]}>
       
        <FormProvider {...methods}>
          <View style={[t.flexCol]}>
            <PatientForm /> // <<Child component
            <PrimaryButton
              style={[t.pL3, t.h10]}
              onPress={handleSubmit(onSubmit, onError)}
            >
              Save changes
            </PrimaryButton>
          </View>
        </FormProvider>
      </Row>
    </View>

子组件

  const {
    control,
    register,
    getValues,
    setValue,
    errors,
    defaultValuesRef,
  } = useFormContext();

  console.log('errors:>>', errors); // NOt able to log
  console.log('Identity | getValues>', getValues());
  return (
    <DetailCard title="Identity">
      <Controller
        control={control}
        render={(props) => {
          const { onChange, onBlur, value } = props;
          return (
            <SecondaryInput
              label="Legal First Name"
              value={value}
              onTextChange={(value) => onChange(value)}
              onBlur={onBlur}
            />
          );
        }}
        name="patientIdentity.firstName"
        rule={register({
          required: ' name cannot be empty',
          })}
        defaultValue=""
      />
      <Controller
        control={control}
        as={({ onChange, onBlur, value }) => {
          return (
            <SecondaryInput
              label="Legal Last Name"
              value={value}
              onTextChange={(value) => onChange(value)}
              onBlur={onBlur}
            />
          );
        }}
        name="patientIdentity.lastName"
        rules={{
          required: 'this is required field',
          message: 'required field',
        }}
        defaultValue=""
      />
</DetailCard>
)

Answer 1

您需要检查几件事：

schema 对象不依赖于任何 local-scoped 变量。您可以将它放在函数之外，这样组件就不会在每次渲染时都重新创建它
首先将是的 schema 对象传递给 yupResolver，而不是直接传递给 resolver

import React from 'react';
import { useForm } from 'react-hook-form';
import { yupResolver } from '@hookform/resolvers/yup';
import * as yup from "yup";

const schema = yup.object().shape({
  patientIdentity: yup.object().shape({
    firstName: yup.string().required('Required field'),
    lastName: yup.string().required('Required field'),
  }),
});

const App = () => {
  const { ... } = useForm({
    resolver: yupResolver(schema),
  });

  return (...);
};

如果您使用 third-party 库编写验证规则，例如 Yup，您可以从 Controller 中删除 rules 道具，因为它们是重复的。

如何在 `react-hook-form` 库中将 Yup 验证模式与 Controller 组件一起使用

How to use Yup validation schema with the Controller component in `react-hook-form` lib

forms

reactjs

react-native

yup

react-hook-form

父组件

子组件