是的，没有使用 Formik，也没有提供任何类型的错误

Question

是的验证不工作我也试过这样import Yup from 'yup'但仍然不工作..，当我创建一个没有 YUP 的简单验证函数时它工作正常。但是当我使用 YUP 时验证不起作用。 添加了表单组件

import React from 'react';
import { useFormik } from 'formik';
import * as Yup from 'yup';

const initialValues = {
    name : "",
    surname : "",
    address : ""
}

const validateSchema = Yup.object({
 name: Yup.string().required('This Field is Required'),
 surname: Yup.string().required('This Field is Required'),
 address: Yup.string().required('This Field is Required')
});

const  onSubmit =  values =>{                        
    console.log('FormData->',values);
}

function Form() {
    const formik = useFormik({
        initialValues ,
        onSubmit ,
        validateSchema 
    })
    return (
        <div className="container x col-md-4 col-md-offset-4"  >
         <form onSubmit={formik.handleSubmit} >   
            <div className="form-group">
                <input autoComplete="off" onBlur={formik.handleBlur} onChange={formik.handleChange} 
                value={formik.values.name}  name="name"  className="name form-control-lg" placeholder="Enter A Name" />
                <small> 
                    {formik.touched.name && formik.errors.name ? <div className="error"> {formik.errors.name}  </div> : null} 
                </small>
            </div>
            <div className="form-group">
                <input autoComplete="off" onBlur={formik.handleBlur} onChange={formik.handleChange} 
                value={formik.values.surname}  name="surname" className="surname form-control-lg" placeholder="Enter A Surname" />
                <small> { formik.touched.surname && formik.errors.surname ? <div className="error"> {formik.errors.surname}  </div> : null} </small>
            </div>
            <div className="form-group">    
                <input autoComplete="off" onBlur={formik.handleBlur} onChange={formik.handleChange} value={formik.values.address}
                  name="address" className="address form-control-lg" placeholder="Enter A Address" />
                <small> {formik.touched.address  &&  formik.errors.address ? <div className="error"> {formik.errors.address}  </div> : null} </small>
            </div>
            <button className="btn btn-danger" >Submit</button>
        </form>
    </div>
    )
}
export default Form;

Answer 1

此处的有效选项是 validationSchema 而不是 validateSchema。设置正确的：

const validationSchema = Yup.object({
  // ...
});

useFormik({
  // ...
  validationSchema
})

Answer 2

要使用 formik 和 yup，首先要执行 npm install yup 和 npm install formik。如果您的 yarn 用户然后执行 yarn add formik 和 yarn add yup。

之后遵循此代码。

import {Formik} from 'formik';
import * as yup from 'yup';
//functional component am using
export const Auth = () => {
const initialFormValue ={
email: '',password: '',};
const SignInSchema = yup.object().shape({
email: yup.string().email('Invalid Email').required('Email is Required'),
password: yup.string().min(5, 'Too Short').required('Password is Required'),
})
<Formik initialValues={initialFormValue} validationSchema={SignInSchema}
 onSubmit={values => console.log(values)}>
 {({values, errors, touched, handleChange, handleBlur,
handleSubmit,isSubmitting,
isValid}) => (
 <>
 <input name='email' type='email' handleChange={handleChange} value=
 {values.email} onBlur={handleBlur} label='Email' />
{errors.email && touched.email ? (<Error>{errors.email}</Error>): null}
<input name='password' type='password' handleChange={handleChange} value=
{values.password} onBlur={handleBlur} label='Password' />
{errors.password && touched.password ? (<Error>{errors.password}</Error>):
null}
<button onClick={handleSubmit} type="submit">Send</button>
 </>
) }
 </Formik>
)}

您不必在外部定义初始值，您也可以在 formik 内部定义 <Formik initialValues={email: '', password: ''}> </Formik> 希望对你有帮助谢谢。

是的，没有使用 Formik，也没有提供任何类型的错误

Yup Was Not Working With Formik and also not provide any type of error

reactjs

yup

formik