使用循环为不同的结构变量分配不同的值

Question

我有一个如下所示的考生结构（每个都有 1 个 ID 和他们不同科目的分数）：

struct Examinee
{
    string id;
    float math, literature, physic, chemistry, biology, history, geography, civic_education, natural_science,
          social_science, foreign_language;
};

现在我想编写一个函数，从字符串中读取不同的值并将它们分配给考生。字符串看起来像这样（每个信息用逗号分隔）：

BD1200001,9,4.0,5.0,10,3.5,7.5,4.25,7.0,7.75,9.25,2.0

这是我目前所做的：

Examinee readExaminee(string line_info) {

//turn line_info to char*
    int Line_info_length = line_info.length();
    char* info = new char[Line_info_length + 1];
    strcpy(info, line_info.c_str());

//create examinee
    Examinee examinee;

//read id into examinee by token
    char* token = strtok(info, ",");
    examinee.id = token;

//read score and assign to subjects
    while (token != NULL)
    {
        float score = strtof(token, NULL);

        //assign score to appropriate subject

        token = strtok(NULL, ",");
    }

    delete[] info;
    return examinee;
}

问题是：我可以像上面那样在 while 循环中将每个分数分配给每个主题吗？我怎样才能做到这一点？如果不是，手动分配每个分数是唯一的方法吗？

Answer 1

我会更改 Examinee 的设计。这些方面的内容：

struct Examinee
{
  enum Subject {kSubjMath, kSubjLiterature, ..., kSubjForeignLanguage, kSubjCount};
  string id;
  float scores[kSubjCount];
};

这样您就可以循环访问分数，例如

for (int subj = 0; subj < Examinee::kSubjCount; ++subj) {
 examinee.scores[subj] = some_score;
}

或访问特定分数 examinee.scores[Examinee::kSubjLiterature]

如果您不能或不愿意更改 Examinee，您可以在本地进行模拟：

Examinee examinee;
float* scores[] = {&examinee.math, &examinee.literature, ..., &examinee.foreign_language};
for (int subj = 0; subj < std::extent_v<scores>; ++subj) {
  *scores[subj] = some_value;
}

使用循环为不同的结构变量分配不同的值

Assign different values to different struct variables using loop

c++

string

loops

struct

assign