$_FILES、$_POST、$_SERVER 的具体 5 种方式

Question

concrete5 等同于什么

if (empty($_FILES) && 
    empty($_POST) && 
    isset($_SERVER['REQUEST_METHOD']) && 
    strtolower($_SERVER['REQUEST_METHOD']) == 'post') {

请求方式？

[更新] 看起来这是可行的：

if (empty($this->request->files->all()) && 
    empty($this->request->request->all()) && 
    null !== $this->request->server->get('REQUEST_METHOD') && 
    strtolower($this->request->server->get('REQUEST_METHOD')) == 'post') {

Answer 1

您应该获取当前的 Request 实例。在控制器方法中，它就像写

一样简单

$request = $this->request;

如果您使用的不是控制器而是自定义 class，您可以将请求标记为 class 的依赖项：

use Concrete\Core\Http\Request;

class YourClass
{
    /**
     * @var \Concrete\Core\Http\Request
     */
    private $request;

    public function __construct(Request $request)
    {
        $this->request = $request;
    }

    public function TheMethodWhereYouNeedRequest()
    {
        $request = $this->request;
        // ...
    }
}

也可以通过写

获取Request实例

$request = \Core::make(\Concrete\Core\Http\Request::class);

一旦你有了 Request 实例，你就可以写：

if (
    // Same as empty($_FILES)
    $this->request->files->count() === 0
    &&
    // Same as empty($_POST)
    $this->request->request->count() === 0
    &&
    // Same as isset($_SERVER['REQUEST_METHOD']) && strtolower($_SERVER['REQUEST_METHOD']) == 'post'
    $this->request->getMethod() === 'POST'
) {
    ...
}

请注意，concrete5 Request 扩展了 Symfony Request（版本 3.4），因此您可能想看看 https://symfony.com/doc/3.4/components/http_foundation.html#accessing-request-data

$_FILES、$_POST、$_SERVER 的具体 5 种方式

concrete5 way for $_FILES, $_POST, $_SERVER

concrete5