JSON 数据不是来自本地主机
JSON data is not coming from local host
我正在尝试从本地主机获取 json 数据。我已经做过很多次了。但是这次不是取数据。
Json数据
{
"swimming_pool":"0",
"security":"0",
"lift":"0",
"gym":"0",
"reserved_parking":"0",
"visitor_parking":"0",
"power_backup":"0",
"servant_room":"0",
"tennis_court":"0",
"rainwater_harvesting":"0",
"waste_management":"0",
"club_house":"0",
"desc":"Dkkd",
"city":"City",
"pincode":"Pin Co",
"locality":"locality",
"no_of_beds":"1",
"no_of_baths":"4"
}
客户端代码
{
NSString *selectQuery=[NSString stringWithFormat:@"http://localhost/FilterQuery.php?swimming_pool=%li&&security=%li&&lift=%li&&gym=%li&&visitor_parking=%li&&power_backup=%li&&servant_room=%li&&rainwater_harvesting=%li&&waste_management=%li&&clubhouse=%li&&Posdesc=%@&&no_of_baths=%li&&no_of_beds=%li&&pincode=%li&&locality=%@&&protypedesc=%@",(long)swimpoolb,(long)securityb,(long)liftb,(long)gymb,(long)visparkingb,(long)pbu,(long)servantroom,(long)rainwaterh,(long)wastemanagement,(long)clubHouse,possesion,(long)bathrooms,(long)bedrooms,(long)zipcode,locality,propertyType];
NSString *newInsrStr = [selectQuery stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSData *dataaa=[NSData dataWithContentsOfURL:[NSURL URLWithString:newInsrStr]];
NSString *rr=[[NSString alloc]initWithData:dataaa encoding:NSUTF8StringEncoding];
NSLog(@"%@",rr);
jsondataa=[NSJSONSerialization JSONObjectWithData:dataaa options:0 error:nil];
//jsondataa is dictionary
swimmingPool=@"";
swimmingPool=[jsondataa objectForKey:@"swimming_pool"];
security=@"";
security=[jsondataa objectForKey:@"security"];
lift=@"";
lift=[jsondataa objectForKey:@"lift"];
gym=@"";
gym=[jsondataa objectForKey:@"gym"];
reserved_parking=@"";
reserved_parking=[jsondataa objectForKey:@"reserved_parking"];
visitor_parking=@"";
visitor_parking=[jsondataa objectForKey:@"visitor_parking"];
power_backUp=@"";
power_backUp=[jsondataa objectForKey:@"power_backup"];
NSLog(@"%@,%@,%@,%@,%@,%@,%@",swimmingPool,security,lift,gym,reserved_parking,visitor_parking,power_backUp);
}
输出：
2015-06-29 15:20:51.874 NexGV1[1684:60b]
Notice:
Undefined variable: tennis_court in
/Applications/XAMPP/xamppfiles/htdocs/FilterQuery.php on line
21
{"swimming_pool":"0","security":"0","lift":"0","gym":"0","reserved_parking":"0","visitor_parking":"0","power_backup":"0","servant_room":"0","tennis_court":"0","rainwater_harvesting":"0","waste_management":"0","club_house":"0","desc":"Dkkd","city":"City","pincode":"Pin
Co","locality":"locality","no_of_beds":"1","no_of_baths":"4"}
2015-06-29 15:20:51.875 NexGV1[1684:60b]
(null),(null),(null),(null),(null),(null),(null)
显示空值。为什么？
这应该是评论，但评论太长了..
因此，您的方法是 json 通过 url 请求，它不是像这样的东西的理想选择，它令人困惑且难以阅读..
我懒得查那么长url，所以我就介绍一下这种方法..
NSString *selectQuery=[NSString stringWithFormat:@"http://localhost/FilterQuery.php?swimming_pool=%li&&security=%li&&lift=%li&&gym=%li&&visitor_parking=%li&&power_backup=%li&&servant_room=%li&&rainwater_harvesting=%li&&waste_management=%li&&clubhouse=%li&&Posdesc=%@&&no_of_baths=%li&&no_of_beds=%li&&pincode=%li&&locality=%@&&protypedesc=%@",(long)swimpoolb,(long)securityb,(long)liftb,(long)gymb,(long)visparkingb,(long)pbu,(long)servantroom,(long)rainwaterh,(long)wastemanagement,(long)clubHouse,possesion,(long)bathrooms,(long)bedrooms,(long)zipcode,locality,propertyType];
NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:selectQuery]];
您可以将 url 转换为请求，然后使用下面的 NSURLConnection..
__block NSMutableData *fragmentData = [NSMutableData data];
__block id serializedResponse;
[[NSOperationQueue mainQueue] cancelAllOperations];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error)
{
[fragmentData appendData:data];
if ([data length] == 0 && error == nil)
{
NSLog(@"No response from server");
}
else if (error != nil && error.code == NSURLErrorTimedOut)
{
NSLog(@"Request time out");
}
else if (error != nil)
{
NSLog(@"Unexpected error occur: %@", error.localizedDescription);
}
else if ([data length] > 0 && error == nil)
{
if ([fragmentData length] == [response expectedContentLength])
{
NSLog(@"Received %f of data from server.", (CGFloat)[response expectedContentLength]);
serializedResponse = [NSJSONSerialization JSONObjectWithData:data
options:NSJSONReadingAllowFragments
error:&error];
NSLog(@"%@", serializedResponse);
// or
NSLog(@"%@", [[NSString alloc] initWithData:fragmentData encoding:NSUTF8StringEncoding]);
}
}
}];
如果您喜欢使用上面的 NSURLConnection 发出请求的简单方法。
- (NSURLRequest *)convertToRequest:(NSString *)stringURL withDictionary:(NSDictionary *)dictionary
{
NSError *error = nil;
NSData *JSONData = [NSJSONSerialization dataWithJSONObject:dictionary options:0 error:&error];
NSURL *url = [NSURL URLWithString:stringURL];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setHTTPBody: JSONData];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept-Encoding"];
[request setValue:[NSString stringWithFormat:@"%lu", (unsigned long)[JSONData length]] forHTTPHeaderField:@"Content-Length"];
return request;
}
并像这样使用它：
NSDictionary *jsonDictionary = @{
@"swimming_pool": [NSNumber numberWithLong:(long)swimpoolb],
@"security" : [NSNumber numberWithLong:(long)securityb],
.. and so on
};
NSURLRequest *request = [ImplementationClass convertToRequest:YourServerURL withDictionary: jsonDictionary];
在服务器中应该是：
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$json_decoded = json_decode($jsonInput,true);
$json_decoded['swimming_pool'];
$json_decoded['security'];
希望这对您有所帮助...
我正在尝试从本地主机获取 json 数据。我已经做过很多次了。但是这次不是取数据。
Json数据
{
"swimming_pool":"0",
"security":"0",
"lift":"0",
"gym":"0",
"reserved_parking":"0",
"visitor_parking":"0",
"power_backup":"0",
"servant_room":"0",
"tennis_court":"0",
"rainwater_harvesting":"0",
"waste_management":"0",
"club_house":"0",
"desc":"Dkkd",
"city":"City",
"pincode":"Pin Co",
"locality":"locality",
"no_of_beds":"1",
"no_of_baths":"4"
}
客户端代码
{
NSString *selectQuery=[NSString stringWithFormat:@"http://localhost/FilterQuery.php?swimming_pool=%li&&security=%li&&lift=%li&&gym=%li&&visitor_parking=%li&&power_backup=%li&&servant_room=%li&&rainwater_harvesting=%li&&waste_management=%li&&clubhouse=%li&&Posdesc=%@&&no_of_baths=%li&&no_of_beds=%li&&pincode=%li&&locality=%@&&protypedesc=%@",(long)swimpoolb,(long)securityb,(long)liftb,(long)gymb,(long)visparkingb,(long)pbu,(long)servantroom,(long)rainwaterh,(long)wastemanagement,(long)clubHouse,possesion,(long)bathrooms,(long)bedrooms,(long)zipcode,locality,propertyType];
NSString *newInsrStr = [selectQuery stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSData *dataaa=[NSData dataWithContentsOfURL:[NSURL URLWithString:newInsrStr]];
NSString *rr=[[NSString alloc]initWithData:dataaa encoding:NSUTF8StringEncoding];
NSLog(@"%@",rr);
jsondataa=[NSJSONSerialization JSONObjectWithData:dataaa options:0 error:nil];
//jsondataa is dictionary
swimmingPool=@"";
swimmingPool=[jsondataa objectForKey:@"swimming_pool"];
security=@"";
security=[jsondataa objectForKey:@"security"];
lift=@"";
lift=[jsondataa objectForKey:@"lift"];
gym=@"";
gym=[jsondataa objectForKey:@"gym"];
reserved_parking=@"";
reserved_parking=[jsondataa objectForKey:@"reserved_parking"];
visitor_parking=@"";
visitor_parking=[jsondataa objectForKey:@"visitor_parking"];
power_backUp=@"";
power_backUp=[jsondataa objectForKey:@"power_backup"];
NSLog(@"%@,%@,%@,%@,%@,%@,%@",swimmingPool,security,lift,gym,reserved_parking,visitor_parking,power_backUp);
}
输出：
2015-06-29 15:20:51.874 NexGV1[1684:60b]
Notice: Undefined variable: tennis_court in /Applications/XAMPP/xamppfiles/htdocs/FilterQuery.php on line 21
{"swimming_pool":"0","security":"0","lift":"0","gym":"0","reserved_parking":"0","visitor_parking":"0","power_backup":"0","servant_room":"0","tennis_court":"0","rainwater_harvesting":"0","waste_management":"0","club_house":"0","desc":"Dkkd","city":"City","pincode":"Pin Co","locality":"locality","no_of_beds":"1","no_of_baths":"4"} 2015-06-29 15:20:51.875 NexGV1[1684:60b] (null),(null),(null),(null),(null),(null),(null)
显示空值。为什么？
这应该是评论，但评论太长了..
因此，您的方法是 json 通过 url 请求，它不是像这样的东西的理想选择，它令人困惑且难以阅读..
我懒得查那么长url，所以我就介绍一下这种方法..
NSString *selectQuery=[NSString stringWithFormat:@"http://localhost/FilterQuery.php?swimming_pool=%li&&security=%li&&lift=%li&&gym=%li&&visitor_parking=%li&&power_backup=%li&&servant_room=%li&&rainwater_harvesting=%li&&waste_management=%li&&clubhouse=%li&&Posdesc=%@&&no_of_baths=%li&&no_of_beds=%li&&pincode=%li&&locality=%@&&protypedesc=%@",(long)swimpoolb,(long)securityb,(long)liftb,(long)gymb,(long)visparkingb,(long)pbu,(long)servantroom,(long)rainwaterh,(long)wastemanagement,(long)clubHouse,possesion,(long)bathrooms,(long)bedrooms,(long)zipcode,locality,propertyType];
NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:selectQuery]];
您可以将 url 转换为请求，然后使用下面的 NSURLConnection..
__block NSMutableData *fragmentData = [NSMutableData data];
__block id serializedResponse;
[[NSOperationQueue mainQueue] cancelAllOperations];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error)
{
[fragmentData appendData:data];
if ([data length] == 0 && error == nil)
{
NSLog(@"No response from server");
}
else if (error != nil && error.code == NSURLErrorTimedOut)
{
NSLog(@"Request time out");
}
else if (error != nil)
{
NSLog(@"Unexpected error occur: %@", error.localizedDescription);
}
else if ([data length] > 0 && error == nil)
{
if ([fragmentData length] == [response expectedContentLength])
{
NSLog(@"Received %f of data from server.", (CGFloat)[response expectedContentLength]);
serializedResponse = [NSJSONSerialization JSONObjectWithData:data
options:NSJSONReadingAllowFragments
error:&error];
NSLog(@"%@", serializedResponse);
// or
NSLog(@"%@", [[NSString alloc] initWithData:fragmentData encoding:NSUTF8StringEncoding]);
}
}
}];
如果您喜欢使用上面的 NSURLConnection 发出请求的简单方法。
- (NSURLRequest *)convertToRequest:(NSString *)stringURL withDictionary:(NSDictionary *)dictionary
{
NSError *error = nil;
NSData *JSONData = [NSJSONSerialization dataWithJSONObject:dictionary options:0 error:&error];
NSURL *url = [NSURL URLWithString:stringURL];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setHTTPBody: JSONData];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept-Encoding"];
[request setValue:[NSString stringWithFormat:@"%lu", (unsigned long)[JSONData length]] forHTTPHeaderField:@"Content-Length"];
return request;
}
并像这样使用它：
NSDictionary *jsonDictionary = @{
@"swimming_pool": [NSNumber numberWithLong:(long)swimpoolb],
@"security" : [NSNumber numberWithLong:(long)securityb],
.. and so on
};
NSURLRequest *request = [ImplementationClass convertToRequest:YourServerURL withDictionary: jsonDictionary];
在服务器中应该是：
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$json_decoded = json_decode($jsonInput,true);
$json_decoded['swimming_pool'];
$json_decoded['security'];
希望这对您有所帮助...