在 C++ 中将十六进制字符串转换为无符号字符

Question

如何转换？我希望转换后的结果为 1.

#include <iostream>
#include <string>

int main(int argc, const char * argv[]) {
    std::string s = "0x00";
    // insert code here...
    unsigned char* str_hex = (unsigned char*)s.c_str();
    
    unsigned char target = 0x00;
    
    std::cout << "result: " << (*str_hex == target) << "\n";
    return 0;
}

Answer 1

像这样：// #include <string>

std::string s = "0x4A";
unsigned char ch = std::stoul(s, nullptr, 16); // 'J' (Since C++11)

或者像这样：// #include <cstdio>

std::string s = "0x4B";
unsigned char ch = '[=11=]';
sscanf(s.c_str(), "%x", &ch); // 'K' (C library function)

在 C++ 中将十六进制字符串转换为无符号字符

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