我如何配置 `stdin` 以从 C++ 字符串中读取？

Question

考虑一个 cpp 函数 solve()。数字字符串 a（示例测试字符串）作为参数传递给函数 solve()。我希望 stdin 读取字符串 a.

中的数字

其实就是压力测试。因此，在此压力测试中，此函数 solve() 提供了一个字符串 return 结果，该结果将与从另一个函数 solveFast().

获得的另一个结果进行测试

NOTE:- Algorithm in the function solve() is already given to us. I wish to stress-test this algorithm against my own algorithm (in solveFast()). It is guaranteed that Algorithm in the function solve() provides the correct output against its test inputs

#include <bits/stdc++.h>

using namespace std;

int solve(string s) {
    // below given: an algorithm that 
    //uses stdin to take input sample test case (i.e.,not string s)
    int n; //number of integers in string s

    //ignore the purpose of the code below. 
    //Just observe that it is taking the inputs as cin (not from string s.
    cin >> n;
    int first, second, large; 
    for (int i = 0; i < n - 1; i++) {
        if (i == 0) {
            cin >> first >> second;
            large = (second > first) ? second : first;
            if (second < first) first = second;
        } else {
            cin >> second;  // new num
            if (second > large) {
                first = large;
                large = second;
            }
            else if(second > first){
                first = second;
            }
        }
    }
    int result = large * first;

    return result;
}
int solveFast(string s) {
    
    /*
     * my solution here
     */

    return result;
}

int32_t main() {

    //stress-testing code starts here
    while (true) {
        
        string a;

        /*
         * generating a sample test case and storing it in a string 'a'
         */

        int res1 = solve(a);
        int res2 = solveFast(a);
        if(res1!=res2){
            cout << "Wrong answer: " << res1 << " " << res2 << endl;
            break;
        }
        else{
            cout << "OK\n";
        }
    }
    //stress-testig code ends

    /*
    for (int i = 1; i <= t; ++i) {
        int n;
        cin >> n;
        vector<int> numbers(n);
        for (int i = 0; i < n; i++) {
            cin >> numbers[i];
        }
        auto result = solve(numbers);
        cout << result << endl;
    }
    */

    return 0;
}

Answer 1

将 std::istream 传递给您的函数，然后从字符串构造一个 istream。作为一般规则，不要在要进行单元测试的代码中使用全局变量（如 std::cin）。

#include <sstream>
#include <iostream>
int solve(std::istream& input, std::string s) {
     std::string variable;
     input >> variable;
     return 0;
}
void unit_test_solve() {
     std::istringstream input("some string");
     solve(input, "bla");
}
int real_code() {
     solve(std::cin, "bla");
}

我如何配置 `stdin` 以从 C++ 字符串中读取？

how do i configure `stdin` to read from a c++ string?

c++

stdin

stress-testing