创建以变量作为文件名的文本文件

Question

我正在尝试创建一个新的文本文件，并将一个变量指定为文件名；将今天的日期添加到创建的每个文件。尽管继续收到相同的错误-

FileNotFoundError: [Errno 2] No such file or directory: 'TestFileWrite_10/11/2020.txt'

我试过这些方法都没有成功-

使用 str-

today = date.today()
filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")
f = open(str(filename)+'.txt', "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

使用 %-

today = date.today()
filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")
f = open("%s.txt" % filename, "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

使用.format-

today = date.today()
filename = "TestFileWrite" + str(today.strftime("%d/%m/%Y"))
f = open("{}.txt".format(filename), "w")
f.write(output1)
# output1 var is referenced within another part of the script.
f.close()

Answer 1

您必须删除或替换以下斜杠：

filename = "TestFileWrite_" + today.strftime("%d/%m/%Y")

应更改日期格式，例如：

filename = "TestFileWrite_" + today.strftime("%Y%m%d")

或

filename = "TestFileWrite_" + today.strftime("%d_%m_%Y")

另外，'filename'的类型已经是'str'，所以不需要使用str()函数：

f = open(filename+'.txt', 'w')

创建以变量作为文件名的文本文件

Creating Text File with Variable as the File Name

python

filenames

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python-3.x