TypeError: can only concatenate str (not "NoneType") to str python boto3

Question

我已经写下 python boto3 脚本来读取 json 文件。在阅读 json 文件时，我使用 argparse 添加了一些参数。调用脚本时，它抛出以下错误：

这是代码

#!/usr/bin/env python
import json
import sys
import os
import re
import boto3
import argparse

def init():
    global pa
    parser = argparse.ArgumentParser(description='Additional Params.')
    parser.add_argument('--Tier', nargs='?', dest='Tier', required=False, help='Tier')
    parser.add_argument('--BusinessUnit', nargs='?', dest='BusinessUnit', required=False, help='BusinessUnit')
    parser.add_argument('--LineOfBusiness', nargs='?', dest='LineOfBusiness', required=False, help='LineOfBusiness')
    parser.add_argument('--branchName', nargs='?', dest='branchName', required=False, help='branchName')
    parser.add_argument('--ProjectName', nargs='?', dest='ProjectName', required=False, help='ProjectName')
    parser.add_argument('--ContextPath', nargs='?', dest='ContextPath', required=False, help='ContextPath')
    pa = parser.parse_args()


def update_secret():
    init()
    with open('application-' + pa.Tier + '.properties.json') as f:
        baselist = json.load(f)

    client = boto3.client('secretsmanager', region_name='us-east-1')
    config_secret = get_secret()

    for secrets in baselist:
        response = client.update_secret(SecretId=pa.BusinessUnit + "/" + pa.LineOfBusiness + "/" + pa.ProjectName + "/" + pa.branchName + pa.ContextPath + "/" + 'application_' + pa.Tier, SecretString=baselist[secrets][1:])
    print(response)

if __name__ == '__main__':
    update_secret()

[Container] 2020/11/09 20:13:46 Running command python updateSecrets.py --Tier $Tier --BusinessUnit $BusinessUnit --LineOfBusiness $LineOfBusiness --ProjectName ProjectName --ContextPath $ContextPath --branchName $branchName
Traceback (most recent call last):
  File "updateSecrets.py", line 81, in <module>
    update_secret()
  File "updateSecrets.py", line 30, in update_secret
    with open('application-' + pa.Tier + '.properties.json') as f:
TypeError: can only concatenate str (not "NoneType") to str

Answer 1

您正在尝试将字符串与具有 None 值

的变量连接

with open('application-' + pa.Tier + '.properties.json') as f:
# pa.Tier returns None here

Answer 2

在传递命令行参数时，不要使用“$”符号作为值。 $ 不是必需的。下面是我写的用于测试的最少代码。

#!/usr/bin/env python
import argparse

def init():
    global pa
    parser = argparse.ArgumentParser(description='Additional Params.')
    parser.add_argument('--Tier', nargs='?', dest='Tier', required=False, help='Tier')
    pa = parser.parse_args()


def update_secret():
    init()
    print('application-' + pa.Tier + '.properties.json')

if __name__ == '__main__':
    update_secret()

运行以上程序，命令行参数如下。

python3 test.py --Tier abc

它在输出下方打印

application-abc.properties.json

TypeError: can only concatenate str (not "NoneType") to str python boto3

TypeError: can only concatenate str (not "NoneType") to str python boto3

python

json

python-3.x

boto3

aws-secrets-manager