Python 排序并删除列表中的重复项 re.sub

Question

我是 Python 的新手。我尝试制作模拟 bash 命令：cat domains.txt |sort -u|sed 's/^*.//g' > domains2.txt 文件域包含带和不带掩码前缀 *. 的域列表，例如：

*.example.com
example2.org

大约 300k+ 行

我写了这段代码：

infile = "domains.txt"
outfile = "2"
outfile2 = "3"
with open(infile) as fin, open(outfile, "w+") as fout:
    for line in fin:
       line = line.replace('*.', "")
       fout.write(line)
with open('2', 'r') as r, open(outfile2, "w") as fout2 :
    for line in sorted(r):
        print(line, end='',file=fout2)

按计划削减*.，排序列表，但不删除重复行

我曾建议使用 re.sub 而不是 replace 来使模式更严格（就像在 sed 中，我从行首开始这样做），但是当我尝试这样做时：

import re

infile = "domains.txt"
outfile = "2"
outfile2 = "3"
with open(infile) as fin, open(outfile, "w+") as fout:
    for line in fin:
       newline = re.sub('^*.', '', line)
       fout.write(newline)
with open('2', 'r') as r, open(outfile2, "w") as fout2 :
    for line in sorted(r):
        print(line, end='',file=fout2)

它只是对错误不起作用，我不明白。

Answer 1

在正则表达式中，*、.等都是特殊字符。您应该转义它们才能使用它们。

import re

s = "*.example.com"
re.sub(r'^\*\.', '', s)

> 'example.com'

Python 排序并删除列表中的重复项 re.sub

Python sort and delete duplicates in list an use re.sub

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