file_put_contents() 期望参数 1 是有效路径，给定的字符串

Question

我有以下简单脚本（精简）：

define("LANG_DIR", "../../app/lang/");
// define("LANG_DIR", "/var/www/html/app/lang/");

// #############
// Some parsing of an CSV file, from with we will create .php files
// #############

foreach ($fileContent as $fileName => $value) {
    $fileString = FILE_START;

    foreach ($value as $arrayKey => $arrayValue) {
        $fileString .= TAB . "'" . $arrayKey . "'" . TAB . TAB . "=>" . TAB . TAB .  "'" . $arrayValue . "'," . NL;
    }

    $fileString .= FILE_END;

    $filePath = trim(LANG_DIR . $desLang . "/" . $fileName . ".php");
    echo $filePath;
    file_put_contents($filePath, $fileString);
}

这些是我收到的错误：

../../app/lang/de/behandeling.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/bewaarplaats.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/cron.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/gebruikers.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/handelshuis.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/heftrucks.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61
../../app/lang/de/history.php
Warning: file_put_contents() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 61

当我使用另一个（已注释的）定义时出现同样的错误。

问题是，我在同一文件夹中的另一个脚本中使用了相同的定义，并且我可以从那里访问这些文件。所以路径是对的，只是file_put_contents找不到。

编辑按照@e-Learner 的要求，这是我使用

时得到的输出

var_dump(is_file(LANG_DIR . $desLang . "/" . $fileName . ".php"));

// This will output:

Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 63
NULL

编辑 2 更改了更多代码：

$filePath = trim(LANG_DIR . $desLang . "/" . $fileName . ".php");

echo $filePath . "<br />";
var_dump(is_file("/var/www/html/app/lang/de/behandeling.php"));
var_dump(is_file($filePath));

这将导致：

/var/www/html/app/lang/de/behandeling.php
/var/www/html/app/lang/de/behandeling.php 
bool(true) 
Warning: is_file() expects parameter 1 to be a valid path, string given in /var/www/html/public/scripts/languageImport.php on line 68

如您所见，当我使用整个字符串时，脚本可以访问该文件。但是当我动态创建字符串时（通过插入 $fileName），它出错了......但是两个字符串是相同的

Answer 1

好吧，经过一番折腾，我找到了解决办法，given by @naviciroel

I got the same error before but I don't know if this solution of mine works on your problem you need to remove the "[=10=]" try replace it:

$cleaned = strval(str_replace("[=10=]", "", $buttons_first));

file_put_contents() 期望参数 1 是有效路径，给定的字符串

file_put_contents() expects parameter 1 to be a valid path, string given

php

path

relative-path

file-put-contents