我可以打印数据，但无法将其分配给 Swift 中的标签
I can print data but can't assign it to a label in Swift
我将 API 调用中的数据发送到我的 InfoController viewDidLoad。在那里，我能够安全地将它存储在 skillName 常量中，并打印它，通过控制台接收所有信息。
当我尝试将此变量分配给我的 skillLabel 时出现问题。
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
guard var skillName = names as? String else { return }
self.pokemon?.skillName = skillName
self.allNames = skillName
print(self.allNames)
}
}
在那里，当我打印 allNames 时，控制台显示了我需要的所有数据。数据是这样的：Data Example
我想在其中使用此数据的计算 属性 看起来是：
var pokemon: Pokemon? {
didSet {
guard let id = pokemon?.id else { return }
guard let data = pokemon?.image else { return }
navigationItem.title = pokemon?.name?.capitalized
infoLabel.text = pokemon?.description
infoView.pokemon = pokemon
if id == pokemon?.id {
imageView.image = UIImage(data: data)
infoView.configureLabel(label: infoView.skillLabel, title: "Skills", details: "\(allNames)")
}
}
}
PD: allNames 是我在 InfoController class 级别的字符串变量。
这是我的应用在 运行 时的样子：
PokeApp
我的目标是获取详细信息参数以显示 skillName 数据，但它 returns 没有，我不知道为什么。有什么建议吗？
编辑 1： 我从我的服务 class 获取口袋妖怪数据的功能是这个：
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
DispatchQueue.main.async {
self.pokemon? = poke
guard let skills = poke.abilities else { return }
for skill in skills {
guard let ability = skill.ability else { return }
guard var names = ability.name!.capitalized as? String else { return }
self.pokemon?.skillName = names
handler(names)
}
}
}
}
EDIT2： InfoView class 看起来像：
class InfoView: UIView {
// MARK: - Properties
var delegate: InfoViewDelegate?
// This whole block assigns the attributes that will be shown at the InfoView pop-up
// It makes the positioning of every element possible
var pokemon: Pokemon? {
didSet {
guard let pokemon = self.pokemon else { return }
guard let type = pokemon.type else { return }
guard let defense = pokemon.defense else { return }
guard let attack = pokemon.attack else { return }
guard let id = pokemon.id else { return }
guard let height = pokemon.height else { return }
guard let weight = pokemon.weight else { return }
guard let data = pokemon.image else { return }
if id == pokemon.id {
imageView.image = UIImage(data: data)
}
nameLabel.text = pokemon.name?.capitalized
configureLabel(label: typeLabel, title: "Type", details: type)
configureLabel(label: pokedexIdLabel, title: "Pokedex Id", details: "\(id)")
configureLabel(label: heightLabel, title: "Height", details: "\(height)")
configureLabel(label: defenseLabel, title: "Defense", details: "\(defense)")
configureLabel(label: weightLabel, title: "Weight", details: "\(weight)")
configureLabel(label: attackLabel, title: "Base Attack", details: "\(attack)")
}
}
let skillLabel: UILabel = {
let label = UILabel()
return label
}()
let imageView: UIImageView = {
let iv = UIImageView()
iv.contentMode = .scaleAspectFill
return iv
}()
. . .
}
infoView.configureLabel是这样的：
func configureLabel(label: UILabel, title: String, details: String) {
let attributedText = NSMutableAttributedString(attributedString: NSAttributedString(string: "\(title): ", attributes: [NSAttributedString.Key.font : UIFont.boldSystemFont(ofSize: 16), NSAttributedString.Key.foregroundColor: Colors.softRed!]))
attributedText.append(NSAttributedString(string: "\(details)", attributes: [NSAttributedString.Key.font : UIFont.systemFont(ofSize: 16), NSAttributedString.Key.foregroundColor: UIColor.gray]))
label.attributedText = attributedText
}
编辑 3： 结构设计
struct Pokemon: Codable {
var results: [Species]?
var abilities: [Ability]?
var id, attack, defense: Int?
var name, type: String?
...
}
struct Ability: Codable {
let ability: Species?
}
struct Species: Codable {
let name: String?
let url: String?
}
Jump to the Edit2 paragraph for the final answer!
初始答案：
我看起来像你 UI 在控制器获取所有数据后没有更新。
由于你们所有人 UI 配置代码都在 var pokemon / didSet 中，最好将其提取到单独的方法中。
private func updateView(with pokemon: Pokemon?, details: String?) {
guard let id = pokemon?.id, let data = pokemon?.image else { return }
navigationItem.title = pokemon?.name?.capitalized
infoLabel.text = pokemon?.description
infoView.pokemon = pokemon
if id == pokemon?.id {
imageView.image = UIImage(data: data)
infoView.configureLabel(label: infoView.skillLabel, title: "Skills", details: details ?? "")
}
}
现在您可以轻松调用 didSet
var pokemon: Pokemon? {
didSet { updateView(with: pokemon, details: allNames) }
}
和fetchPokemons完成以及
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
guard var skillName = names as? String else { return }
self.pokemon?.skillName = skillName
self.allNames = skillName
print(self.allNames)
DispatchQueue.main.async {
self.updateView(with: self.pokemon, details: self.allNames)
}
}
}
在主队列上进行任何 UI 设置都非常重要。
编辑：
可能是 fetch 函数导致了问题！您多次调用处理程序：
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
DispatchQueue.main.async {
self.pokemon? = poke
guard let skills = poke.abilities else { return }
let names = skills.compactMap { [=13=].ability?.name?.capitalized }.joined(separator: ", ")
handler(names)
}
}
}
编辑2：
查看您的代码库后，您需要更改几处：
1。 fetchPokemons 实施
controller.service.fetchPokes 的处理程序被 每个 口袋妖怪调用，所以我们需要检查获取的是否是当前的（self.pokemon）然后调用handler 具有正确格式的技能。
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
guard poke.id == self.pokemon?.id else { return }
self.pokemon? = poke
let names = poke.abilities?.compactMap { [=14=].ability?.name?.capitalized }.joined(separator: ", ")
handler(names ?? "-")
}
}
2。更新 viewDidLoad()
现在只需将 names 值传递给标签即可。
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
self.pokemon?.skillName = names
self.infoView.configureLabel(label: self.infoView.skillLabel, title: "Skills", details: names)
}
}
3。重构 var pokemon: Pokemon? didSet observer
var pokemon: Pokemon? {
didSet {
guard let pokemon = pokemon, let data = pokemon.image else { return }
navigationItem.title = pokemon.name?.capitalized
infoLabel.text = pokemon.description!
infoView.pokemon = pokemon
imageView.image = UIImage(data: data)
}
}
我将 API 调用中的数据发送到我的 InfoController viewDidLoad。在那里，我能够安全地将它存储在 skillName 常量中，并打印它，通过控制台接收所有信息。
当我尝试将此变量分配给我的 skillLabel 时出现问题。
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
guard var skillName = names as? String else { return }
self.pokemon?.skillName = skillName
self.allNames = skillName
print(self.allNames)
}
}
在那里，当我打印 allNames 时，控制台显示了我需要的所有数据。数据是这样的：Data Example
我想在其中使用此数据的计算 属性 看起来是：
var pokemon: Pokemon? {
didSet {
guard let id = pokemon?.id else { return }
guard let data = pokemon?.image else { return }
navigationItem.title = pokemon?.name?.capitalized
infoLabel.text = pokemon?.description
infoView.pokemon = pokemon
if id == pokemon?.id {
imageView.image = UIImage(data: data)
infoView.configureLabel(label: infoView.skillLabel, title: "Skills", details: "\(allNames)")
}
}
}
PD: allNames 是我在 InfoController class 级别的字符串变量。
这是我的应用在 运行 时的样子： PokeApp
我的目标是获取详细信息参数以显示 skillName 数据，但它 returns 没有，我不知道为什么。有什么建议吗？
编辑 1： 我从我的服务 class 获取口袋妖怪数据的功能是这个：
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
DispatchQueue.main.async {
self.pokemon? = poke
guard let skills = poke.abilities else { return }
for skill in skills {
guard let ability = skill.ability else { return }
guard var names = ability.name!.capitalized as? String else { return }
self.pokemon?.skillName = names
handler(names)
}
}
}
}
EDIT2： InfoView class 看起来像：
class InfoView: UIView {
// MARK: - Properties
var delegate: InfoViewDelegate?
// This whole block assigns the attributes that will be shown at the InfoView pop-up
// It makes the positioning of every element possible
var pokemon: Pokemon? {
didSet {
guard let pokemon = self.pokemon else { return }
guard let type = pokemon.type else { return }
guard let defense = pokemon.defense else { return }
guard let attack = pokemon.attack else { return }
guard let id = pokemon.id else { return }
guard let height = pokemon.height else { return }
guard let weight = pokemon.weight else { return }
guard let data = pokemon.image else { return }
if id == pokemon.id {
imageView.image = UIImage(data: data)
}
nameLabel.text = pokemon.name?.capitalized
configureLabel(label: typeLabel, title: "Type", details: type)
configureLabel(label: pokedexIdLabel, title: "Pokedex Id", details: "\(id)")
configureLabel(label: heightLabel, title: "Height", details: "\(height)")
configureLabel(label: defenseLabel, title: "Defense", details: "\(defense)")
configureLabel(label: weightLabel, title: "Weight", details: "\(weight)")
configureLabel(label: attackLabel, title: "Base Attack", details: "\(attack)")
}
}
let skillLabel: UILabel = {
let label = UILabel()
return label
}()
let imageView: UIImageView = {
let iv = UIImageView()
iv.contentMode = .scaleAspectFill
return iv
}()
. . .
}
infoView.configureLabel是这样的：
func configureLabel(label: UILabel, title: String, details: String) {
let attributedText = NSMutableAttributedString(attributedString: NSAttributedString(string: "\(title): ", attributes: [NSAttributedString.Key.font : UIFont.boldSystemFont(ofSize: 16), NSAttributedString.Key.foregroundColor: Colors.softRed!]))
attributedText.append(NSAttributedString(string: "\(details)", attributes: [NSAttributedString.Key.font : UIFont.systemFont(ofSize: 16), NSAttributedString.Key.foregroundColor: UIColor.gray]))
label.attributedText = attributedText
}
编辑 3： 结构设计
struct Pokemon: Codable {
var results: [Species]?
var abilities: [Ability]?
var id, attack, defense: Int?
var name, type: String?
...
}
struct Ability: Codable {
let ability: Species?
}
struct Species: Codable {
let name: String?
let url: String?
}
Jump to the Edit2 paragraph for the final answer!
初始答案：
我看起来像你 UI 在控制器获取所有数据后没有更新。
由于你们所有人 UI 配置代码都在 var pokemon / didSet 中，最好将其提取到单独的方法中。
private func updateView(with pokemon: Pokemon?, details: String?) {
guard let id = pokemon?.id, let data = pokemon?.image else { return }
navigationItem.title = pokemon?.name?.capitalized
infoLabel.text = pokemon?.description
infoView.pokemon = pokemon
if id == pokemon?.id {
imageView.image = UIImage(data: data)
infoView.configureLabel(label: infoView.skillLabel, title: "Skills", details: details ?? "")
}
}
现在您可以轻松调用 didSet
var pokemon: Pokemon? {
didSet { updateView(with: pokemon, details: allNames) }
}
和fetchPokemons完成以及
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
guard var skillName = names as? String else { return }
self.pokemon?.skillName = skillName
self.allNames = skillName
print(self.allNames)
DispatchQueue.main.async {
self.updateView(with: self.pokemon, details: self.allNames)
}
}
}
在主队列上进行任何 UI 设置都非常重要。
编辑：
可能是 fetch 函数导致了问题！您多次调用处理程序：
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
DispatchQueue.main.async {
self.pokemon? = poke
guard let skills = poke.abilities else { return }
let names = skills.compactMap { [=13=].ability?.name?.capitalized }.joined(separator: ", ")
handler(names)
}
}
}
编辑2：
查看您的代码库后，您需要更改几处：
1。 fetchPokemons 实施
controller.service.fetchPokes 的处理程序被 每个 口袋妖怪调用，所以我们需要检查获取的是否是当前的（self.pokemon）然后调用handler 具有正确格式的技能。
func fetchPokemons(handler: @escaping (String) -> Void) {
controller.service.fetchPokes { (poke) in
guard poke.id == self.pokemon?.id else { return }
self.pokemon? = poke
let names = poke.abilities?.compactMap { [=14=].ability?.name?.capitalized }.joined(separator: ", ")
handler(names ?? "-")
}
}
2。更新 viewDidLoad()
现在只需将 names 值传递给标签即可。
override func viewDidLoad() {
super.viewDidLoad()
configureViewComponents()
fetchPokemons { (names) in
self.pokemon?.skillName = names
self.infoView.configureLabel(label: self.infoView.skillLabel, title: "Skills", details: names)
}
}
3。重构 var pokemon: Pokemon? didSet observer
var pokemon: Pokemon? {
didSet {
guard let pokemon = pokemon, let data = pokemon.image else { return }
navigationItem.title = pokemon.name?.capitalized
infoLabel.text = pokemon.description!
infoView.pokemon = pokemon
imageView.image = UIImage(data: data)
}
}