Postgresql : ERROR: in creating temp table with list object values

Question

我正在编写一个 Postgresql 函数（使用 pgAdmin GUI），它将从我的 Spring 引导应用程序调用，使用 java 列表对象作为参数

提到了我的实际需求here and with the suggestions to create a temp table with list values to optimize query, following is the Postgres function which I have tried by referring from here:

CREATE FUNCTION public."getInventory"("vals1Arg" character varying[], "vals2Arg" character varying[])
    RETURNS "INVENTORY"
    LANGUAGE 'sql'      
    
AS 
$BODY$
 
// I assume the below two lines create two temp tables and populate the table 
   with my list object values
CREATE TEMP TABLE t1 AS 
          SELECT * FROM VALUES(vals1Arg)

CREATE TEMP TABLE t2 AS 
          SELECT * FROM VALUES(vals2Arg)

SELECT * FROM "INVENTORY"
    where "COLUMN_1" in (select * from t1)
    and "COLUMN_2" in (Select * from t2);  
   
 $BODY$;

以下是我调用 postgres 函数的代码片段

@Query(nativeQuery = true, value = "select \"getInventory\" (:vals1Arg,:vals2Arg)")
    List<Inventory> getInventoryInfo(List<String> vals1Arg, List<String> vals2Arg);

由于列表会很大，我正在创建一个临时的 table，其中包含列表对象参数中的值，并在我的 select 查询

中使用它

提前致谢！！

Answer 1

有几个问题：

CREATE TABLE ... AS的语法应该是

CREATE TABLE ... AS
   SELECT * FROM (VALUES (...)) AS alias;

而不是

CREATE TABLE ... AS
   SELECT * FROM VALUES (...);

您需要这些括号和别名。

查询中的子选择将不起作用，因为它将 varchar (COLUMN_1) 与 varchar[]（临时 table).

要做到这一点，您必须
```
SELECT * FROM "INVENTORY"
   WHERE "COLUMN_1" = ANY (SELECT * FROM t1);
```

如果您想创建临时 table 而不是直接在 SELECT 中使用数组，您最好

CREATE TEMP TABLE t1 AS
   SELECT * FROM unnest(vals1Arg) AS u(c);
CREATE TEMP TABLE t2 AS
   SELECT * FROM unnest(scomoIdList) AS u(c);

ANALYZE t1, t2;

RETURN QUERY SELECT * FROM "INVENTORY"
                JOIN t1 ON "INVENTORY"."COLUMN_1" = t1.c
                JOIN t2 ON "INVENTORY"."COLUMN_2" = t2.c;

这假定列表不包含重复条目。

Postgresql : ERROR: in creating temp table with list object values

Postgresql : ERROR: in creating temp table with list object values

postgresql

spring-data-jpa

postgresql-9.4

pgadmin-4