SQL 服务器 - 根据条件从查询结果集中排除记录
SQL Server - Exclude records from query result set based on condition
使用以下查询,我试图获得每个部门的 FTE 学生平均人数,每个部门的学生总数除以该部门的 FTE 学生总数。
在少数院系中没有 FTE 学生,为此我使用案例陈述将平均值视为 0,在这种情况下没有 FTE 学生(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END)=0 THEN 0
SELECT D.[DepartmentId],
CASE WHEN COUNT(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END)=0 THEN 0
ELSE COUNT(S.[StudentId])/COUNT(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END) END AS 'AverageOfFTEStudents'
FROM dbo.[Student] S
INNER JOIN [dbo].User U
ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D
ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
以上查询给出的结果即使平均为 0,现在我想排除那些平均 FTE 学生为 0 的部门,这意味着没有 FTE 学生。
简而言之'AverageOfFTEStudents'为0的部门应该从我的结果中排除
我想你想要一个 having
子句;您可以使用 AVG()
:
简化计算逻辑
SELECT S.[DepartmentId],
AVG(CASE WHEN [IsFTEStudent] = 1 THEN 1.0 ELSE 0 END) AS [AverageOfFTEStudents]
FROM dbo.[Student] S
INNER JOIN [dbo].User U ON ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
HAVING SUM(CASE WHEN [IsFTEStudent] = 1 THEN 1 ELSE 0 END) > 0
根据 IsFTEStudent
的实际数据类型和值,我们或许可以稍微简化聚合表达式。例如,如果它是具有 0
/1
值的整数,则:
SELECT S.[DepartmentId],
AVG([IsFTEStudent] * 1.0) AS [AverageOfFTEStudents]
FROM dbo.[Student] S
INNER JOIN [dbo].User U ON ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
HAVING SUM([IsFTEStudent]) > 0
使用以下查询,我试图获得每个部门的 FTE 学生平均人数,每个部门的学生总数除以该部门的 FTE 学生总数。
在少数院系中没有 FTE 学生,为此我使用案例陈述将平均值视为 0,在这种情况下没有 FTE 学生(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END)=0 THEN 0
SELECT D.[DepartmentId],
CASE WHEN COUNT(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END)=0 THEN 0
ELSE COUNT(S.[StudentId])/COUNT(CASE U.[IsFTEStudent] WHEN 1 THEN 1 END) END AS 'AverageOfFTEStudents'
FROM dbo.[Student] S
INNER JOIN [dbo].User U
ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D
ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
以上查询给出的结果即使平均为 0,现在我想排除那些平均 FTE 学生为 0 的部门,这意味着没有 FTE 学生。
简而言之'AverageOfFTEStudents'为0的部门应该从我的结果中排除
我想你想要一个 having
子句;您可以使用 AVG()
:
SELECT S.[DepartmentId],
AVG(CASE WHEN [IsFTEStudent] = 1 THEN 1.0 ELSE 0 END) AS [AverageOfFTEStudents]
FROM dbo.[Student] S
INNER JOIN [dbo].User U ON ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
HAVING SUM(CASE WHEN [IsFTEStudent] = 1 THEN 1 ELSE 0 END) > 0
根据 IsFTEStudent
的实际数据类型和值,我们或许可以稍微简化聚合表达式。例如,如果它是具有 0
/1
值的整数,则:
SELECT S.[DepartmentId],
AVG([IsFTEStudent] * 1.0) AS [AverageOfFTEStudents]
FROM dbo.[Student] S
INNER JOIN [dbo].User U ON ON S.[StudentId] = U.[UserId]
INNER JOIN dbo.[Department] D ON D.DepartmentId = S.[DepartmentId]
WHERE D.CollegeId = 5
GROUP BY S.DepartmentId
HAVING SUM([IsFTEStudent]) > 0