AWS CloudWatch 的正确格式

Question

我在 AWS ECS 上运行的 Docker 容器中使用 Servant and colog。

HTTP 请求已完美记录到 AWS CloudWatch，但不是我的手动记录。

我以这种方式启动了我的 WAI 服务器：

main :: IO ()
main = do
  withStdoutLogger $ \aplogger -> do
    let settings = setPort 8080 $ setLogger aplogger defaultSettings
    initializeApplication >>= runSettings settings

我也尝试模仿 Apache Logging 风格：

logStringStdoutCloudWatch :: MonadIO m => LogAction m String
logStringStdoutCloudWatch = LogAction $ \x -> liftIO $ do
  let format = "%d/%b/%Y:%T %z"
  time <- getCurrentTime
  putStrLn $ "- - - [" ++ formatTime defaultTimeLocale format time ++ "] \"log\" - - \"\" \"" ++ x ++ "\""

它给了我以下日志：

- - - [12/Nov/2020:16:36:16 +0000] "log" - - "" "A log message"
127.0.0.1 - - [12/Nov/2020:17:36:16 +0100] "POST /event HTTP/1.1" 400 - "" "Client"

但只有最后一行记录在 CloudWatch 中。

我的格式有什么问题？或者：是否有专门的 lib/function 来获得正确的格式？

Answer 1

实际上我已经作弊将日志格式更改为json，首先在Servant级别：

import Network.Wai.Middleware
import Network.Wai.Middleware.RequestLogger
import Network.Wai.Middleware.RequestLogger.JSON(formatAsJSONWithHeaders)

initializeApplication :: IO Application
initializeApplication = do
  logger <- 
  mkRequestLogger def {outputFormat = CustomOutputFormatWithDetailsAndHeaders formatAsJSONWithHeaders}
  return
    $ logger
    $ serve (Proxy @API)
    $ hoistServer (Proxy @API) (toHandler env) server

main :: IO ()
main = do
  let settings = setPort 8080 defaultSettings
  initializeApplication >>= runSettings settings

和记录器：

logStringStdoutCloudWatch :: MonadIO m => LogAction m String
logStringStdoutCloudWatch = LogAction $ \x -> liftIO $ do
  let format = "%d/%b/%Y:%T %z"
  time <- getCurrentTime
  putStrLn $ "{\"time\":\"" ++ formatTime defaultTimeLocale format time ++ "\",\"log\":\"" ++ x ++ "\"}"

AWS CloudWatch 的正确格式

Correct format for AWS CloudWatch

haskell

logging

amazon-cloudwatch

amazon-cloudwatchlogs

servant