Firebase Locally use config variable doesn't work - Error: Missing Plaid "Secret"

Question

我在本地测试 firebase 功能时遇到问题。我有一些要保护的关键 api 键。所以为此我使用 functions.config().

当使用 firebase emulators:start 或 firebase emulators:start --only functions 在本地启动您的函数服务器时，当使用 functions.config().plaid.secret.[=23 时 secret 值为空时，它向我显示错误=]

我使用 firebase functions:config:get > .runtimeconfig.json 将我的配置带到本地。我运行它在我的 functions 文件夹中。

.runtimeconfig.json 文件如下所示：

{
  "plaid": {
    "secret": "blabla",
    "clientid": "blabla"
  }
}

我的 index.js 如下所示：

// Using Express
const express = require('express');
const app = express();
app.use(express.json());

// Cloud Functions
const functions = require("firebase-functions");

// Cloud Firestore
const admin = require("firebase-admin");
admin.initializeApp();
const database = admin.firestore();

// Plaid
const plaid = require("plaid");
const plaidClient = new plaid.Client({
    clientID: functions.config().plaid.clientid,
    secret: functions.config().plaid.secret,
    env: plaid.environments.development,
});

// Firestore Refs
const usersRef = database.collection("users");

// Token Management
// Create Token
app.post('/get_link_token', async (request, response) => {
    try {
        const clientUserId = "SomeUserID";
        // Create the link_token with all of your configurations
        const tokenResponse = await plaidClient.createLinkToken({
            user: {
                client_user_id: clientUserId,
            },
            client_name: 'someproject',
            products: ['auth', 'transactions'],
            country_codes: ['US'],
            language: 'en',
        });
        response.on({ link_token: tokenResponse.link_token });
    } catch (e) {
        // Display error on client
        return response.send({ error: e.message });
    }
});

我的错误如下：

⚠  functions: The Cloud Firestore emulator is not running, so calls to Firestore will affect production.
⚠  Error: Missing Plaid "secret"
    at new Client (/Users/somedude/Work/someproject/functions/node_modules/plaid/lib/PlaidClient.js:17:11)
    at Object.<anonymous> (/Users/somedude/Work/someproject/functions/index.js:18:21)
    at Module._compile (node:internal/modules/cjs/loader:1083:30)
    at Object.Module._extensions..js (node:internal/modules/cjs/loader:1112:10)
    at Module.load (node:internal/modules/cjs/loader:948:32)
    at Function.Module._load (node:internal/modules/cjs/loader:789:14)
    at Module.require (node:internal/modules/cjs/loader:972:19)
    at require (node:internal/modules/cjs/helpers:88:18)
    at /usr/local/lib/node_modules/firebase-tools/lib/emulator/functionsEmulatorRuntime.js:699:33
    at Generator.next (<anonymous>)
    at fulfilled (/usr/local/lib/node_modules/firebase-tools/lib/emulator/functionsEmulatorRuntime.js:5:58)
    at processTicksAndRejections (node:internal/process/task_queues:93:5)
⚠  We were unable to load your functions code. (see above)

你知道我做错了什么吗？

提前致谢！

编辑：你在这里有更多的上下文 https://github.com/plaid/plaid-node/issues/345 我这边还没解决。

Answer 1

好的，解决方案就是实际使用文档中所说的内容。至此：

const plaidClient = new plaid.Client({
    clientID: functions.config().plaid.clientid,
    secret: functions.config().plaid.secret,
    env: plaid.environments.development,
});

并确保您使用的至少是 7.0.0 版本。由于某些原因，使用npm添加包时，安装的是2.1.0，这是绝对不正确的。

Firebase Locally use config variable doesn't work - Error: Missing Plaid "Secret"

Firebase Locally use config variable doesn't work - Error: Missing Plaid "Secret"

node.js

firebase

plaid

google-cloud-functions

google-cloud-firestore