Ramda 数组到多参数函数

Question

给定字符串 6-10 的输入，我想获得一个数字列表 [6,6.5,7,7.5,8,8.5,9,9.5,10]。

这是我想出的：


const x = "6-10";
const sizeMinMax = R.pipe(R.split('-'), R.map(parseInt))
sizeMinMax(x); //[6,10]

const sizesStepped = (min, max) => R.unfold(minSize => minSize > max ? false : [minSize, minSize + 0.5], min)
sizesStepped(8,10); // [8,8.5,9,9.5,10]

如何将数组 sizeMinMax(x) 的输出通过管道传递给具有 2 个参数的 sizeStepped 函数？

Answer 1

您可以通过实施范围方法在原版 JavaScript 中完成。

const range = (start, stop, step) =>
  Array.from({ length: (stop - start) / step + 1 }, (_, i) => start + i * step);

const x = '6-10';
const [s, e] = x.split('-');
const step = 0.5;
const ret = range(+s, +e, step);
console.log(ret);

Answer 2

将 sizesStepped 换成 R.apply:

const sizeMinMax = R.pipe(R.split('-'), R.map(parseInt))

const sizesStepped = (min, max) => R.unfold(minSize => minSize > max ? false : [minSize, minSize + 0.5], min)

const fn = R.pipe(sizeMinMax, R.apply(sizesStepped));

const x = "6-10"

const result = fn(x)

console.log(result); // [8,8.5,9,9.5,10]

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Ramda 数组到多参数函数

Ramda array to multiple argument function

javascript

functional-programming

ramda.js