Android Kotlin 如何删除列表中的重复值

Question

我正在尝试将 JSON 数据放入微调器中。

val product_sizes = productfeed.variants.joinToString { variants -> variants.option_values[0].name }
    Log.d("TAG", "TESTING:: ${product_sizes} ")

这是输出：

TESTING:: SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL, SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL, SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL, SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL, SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL

我只想将一组尺寸放入微调器中，而不是其中的 5 个。我也试过：

 val product_sizes = productfeed.variants.joinToString { variants -> variants.option_values[0].name.toSet().toList().toString() }
    Log.d("TAG", "TESTING:: ${product_sizes} ")

输出为：

TESTING:: [S, M, A, L], [M, E, D, I, U], [L, A, R, G, E], [1, , X, L], [2, , X, L], [3, , X, L], [S, M, A, L], [M, E, D, I, U], [L, A, R, G, E], [1, , X, L], [2, , X, L], [3, , X, L], [S, M, A, L], [M, E, D, I, U], [L, A, R, G, E], [1, , X, L], [2, , X, L], [3, , X, L], [S, M, A, L], [M, E, D, I, U], [L, A, R, G, E], [1, , X, L], [2, , X, L], [3, , X, L], [S, M, A, L], [M, E, D, I, U], [L, A, R, G, E], [1, , X, L], [2, , X, L], [3, , X, L]

请帮忙。谢谢！

Answer 1

您应该在加入之前将列表转换为 Set，而不是在

之后

val product_sizes = productfeed.variants
                               .map { it.option_values[0].name }
                               .toSet()
                               .joinToString()
Log.d("TAG", "TESTING:: ${product_sizes} ")

然后输出将是

TESTING:: SMALL, MEDIUM, LARGE, 1 XL, 2 XL, 3 XL

您还可以使用 distincBy 来省略 map 运算符。

val product_sizes = productfeed.variants
                               .distincBy { it.option_values[0].name }
                               .joinToString { it.option_values[0].name }
Log.d("TAG", "TESTING:: ${product_sizes} ")

Android Kotlin 如何删除列表中的重复值

Android Kotlin how to Remove duplicate values in a list

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