MySQL Select 两列之间的范围日期，不使用 table 列

Question

在我的 sql 中，我想在不使用 table 列的情况下获取两个日期之间的日期差异例如

SELECT BETWEEN '2012-01-10' AND '2012-01-15' as date1;

我必须得到以下日期作为输出 '2012-01-11' '2012-01-12' '2012-01-13' '2012-01-14'

如何编写查询以获得如上的输出

Answer 1

如果你是运行MySQL8.0，你可以用递归查询来实现：

with recursive cte as (
    select '2012-01-10' + interval 1 day as dt
    union all 
    select dt + interval 1 day from cte where dt + interval 1 day < '2012-01-15'
)
select * from cte

这会在作为输入给出的界限之间为每个日期生成一行。

Answer 2

WITH RECURSIVE
cte AS ( SELECT @startdate + INTERVAL 1 DAY `date`
         UNION ALL
         SELECT `date`+ INTERVAL 1 DAY
         FROM cte 
         WHERE `date` < @enddate - INTERVAL 1 DAY )
SELECT * 
FROM cte

fiddle

MySQL 8+ 需要。

my sql version used 5.6

maximum 1 year

SELECT @startdate + INTERVAL (n3.num * 7 * 7 + n2.num * 7 + n1.num + 1) DAY `date`
FROM  ( SELECT 0 num union select 1 union select 2 union select 3
       union select 4 union select 5 union select 6) n1
JOIN  ( SELECT 0 num union select 1 union select 2 union select 3
       union select 4 union select 5 union select 6) n2
JOIN  ( SELECT 0 num union select 1 union select 2 union select 3
       union select 4 union select 5 union select 6 union select 7) n3
HAVING `date` < @enddate;

fiddle

最大。经期长度为 7 * 7 * 8 = 392 天。

MySQL Select 两列之间的范围日期，不使用 table 列

MySQL Select range date between two columns without using table columns

mysql

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datetime

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