如何对重复项求和 SQL/PSQL
How to sum duplicates SQL/PSQL
我对如何构建一个查询来计算所有重复项的总和有一些问题,在下面的这个查询中我可以计算所有出现的次数。
SELECT COUNT (*) occurrences
FROM back.submission s
GROUP BY s.name
HAVING COUNT(*) > 1
----------
|# |occurrences|
|1 | 9 |
|2 | 6 |
|3 | 5 |
|4 | 4 |
|5 | 4 |
|6 | 3 |
....
我想知道如何对所有出现的事件求和,我尝试将计数放在 SUM 中,但它不起作用
SELECT #,count(*) As Total FROM back.submission GROUP BY # HAVING COUNT(*) > 1;
是否需要其他聚合级别?
SELECT COUNT(occurences) AS count_of_duplicates, SUM(occurences) AS sum_of_duplicates
FROM (
SELECT COUNT (*) occurrences
FROM back.submission s
GROUP BY s.name
HAVING COUNT(*) > 1
) t
With CTE
As
(
Select [#],Count([*]) As Total From back.submission Group By [#]
)
select [#],Total From CTE Where Total>1
我对如何构建一个查询来计算所有重复项的总和有一些问题,在下面的这个查询中我可以计算所有出现的次数。
SELECT COUNT (*) occurrences
FROM back.submission s
GROUP BY s.name
HAVING COUNT(*) > 1
----------
|# |occurrences|
|1 | 9 |
|2 | 6 |
|3 | 5 |
|4 | 4 |
|5 | 4 |
|6 | 3 |
....
我想知道如何对所有出现的事件求和,我尝试将计数放在 SUM 中,但它不起作用
SELECT #,count(*) As Total FROM back.submission GROUP BY # HAVING COUNT(*) > 1;
是否需要其他聚合级别?
SELECT COUNT(occurences) AS count_of_duplicates, SUM(occurences) AS sum_of_duplicates
FROM (
SELECT COUNT (*) occurrences
FROM back.submission s
GROUP BY s.name
HAVING COUNT(*) > 1
) t
With CTE
As
(
Select [#],Count([*]) As Total From back.submission Group By [#]
)
select [#],Total From CTE Where Total>1