在具有更新角色条件的 R 配方中不起作用

Question

如果 variable_names 包含名称，我想将这些角色更新为 Not_predictors；而如果 variable_names 是 NA 我想在函数中跳过这一步。但是，在添加条件时出现错误。请参阅下面的 repex 代码。

# Example Data
pred1 <- c(4,2,1)
pred2 <- c(4,2,1)
pred3 <- c(4,2,1)
pred4 <- c(4,2,1)
id_nr <- c(1, 2, 3)
y <- c(1,5,2)

data <- tibble::tibble(pred1, pred2, pred3, pred4, id_nr, y)

# Want to remove thes variables from predictor role if variable_names is not NA
variable_names <- c("pred1", "pred2")


# Without condition it works
recipe <- data %>%
  recipes::recipe(y ~ .) %>%
  recipes::update_role(id_nr, new_role = "id variable") %>%
  recipes::update_role(dplyr::all_of(variable_names), new_role = "Not_predictors") %>% 
  recipes::step_pca(., recipes::all_predictors(), num_comp = 2) %>% 
  recipes::prep()
recipe


# But when adding the condition I get error. 
recipe <- data %>%
  recipes::recipe(y ~ .) %>%
  recipes::update_role(id_nr, new_role = "id variable") %>%
  {
    if(!is.na(variable_names[1])){
      recipes::update_role(dplyr::all_of(variable_names), new_role = "Not_predictors") 
    } else {
      .
    }
  } %>% 
  recipes::step_pca(., recipes::all_predictors(), num_comp = 2) %>% 
  prep()
recipe

这是错误：

Error: $ operator is invalid for atomic vectors
In addition: Warning message:
No selectors were found

非常感谢任何帮助。

Answer 1

我收到了 RStudio community 的解决方案：

recipe <- data %>%
  recipes::recipe(y ~ .) %>%
  recipes::update_role(id_nr, new_role = "id variable") %>%
  (function(x){
    if(!is.na(variable_names[1])){
      x %>%  recipes::update_role(dplyr::all_of(variable_names), new_role = "Not_predictors") 
    } else {
      x
    }
  }) %>% 
  recipes::step_pca(., recipes::all_predictors(), num_comp = 2) %>% 
  recipes::prep()
recipe

在具有更新角色条件的 R 配方中不起作用

In R recipe with condition to update roles does not work

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