netcdf

Question

我有一个 netcdf 文件，其中包含每日时间步长，我希望将其转换为每月时间步长。时间格式如下：

    double time(time) ;
            time:standard_name = "time" ;
            time:long_name = "time" ;
            time:bounds = "time_bnds" ;
            time:units = "days since 2000-01-01" ;
            time:calendar = "standard" ;
            time:axis = "T" ;

当我使用命令转换为每月时间步长时：

cdo monmean input.nc output.nc

一切正常，除了时间输出很奇怪：

 time = "2000-01-16", "2000-02-15", "2000-03-16", "2000-04-15 12",
"2000-05-16", "2000-06-15 12", "2000-07-16", "2000-08-16",
"2000-09-15 12", "2000-10-16", "2000-11-15 12", "2000-12-16";

我希望将每月值中的日期替换为该月的第一天，并删除出现的时间的那些奇数 12。期望的输出：

 time = "2000-01-01", "2000-02-01", "2000-03-01", "2000-04-01",
"2000-05-01", "2000-06-01", "2000-07-01", "2000-08-01",
"2000-09-01", "2000-10-01", "2000-11-01", "2000-12-01";

感谢任何提示

Answer 1

cdo --timestat_date first monmean input.nc output.nc

适合我，希望对您有所帮助！它将时间戳放在平均周期的第一步，而默认值在中间。（还有一个--timestat_date last 反之则放在window的最后一步）

netcdf - CDO monmean

netcdf - CDO monmean

cdo-climate