Jackson 不会使用自定义序列化器序列化 null

Jackson won't serialize null with a custom Serializer

我有一个我想应用的自定义 bean 序列化程序,但是当我这样做时,Jackson 不再包含 null 属性。

以下代码重现了该问题:

import java.io.IOException;
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.databind.BeanDescription;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationConfig;
import com.fasterxml.jackson.databind.SerializerProvider;
import com.fasterxml.jackson.databind.module.SimpleModule;
import com.fasterxml.jackson.databind.ser.BeanSerializerModifier;
import lombok.Value;

public class Test {

  @Value
  public static class Contact {
    String first;
    String middle;
    String last;
    String email;
  }
  
  
  public static void main(String[] args) throws Exception {
    Contact contact = new Contact("Bob", null, "Barker", null);
    
    ObjectMapper mapper = new ObjectMapper();
    mapper.registerModule(new SimpleModule() {
        @Override public void setupModule(SetupContext context) {
            super.setupModule(context);
            context.addBeanSerializerModifier(new BeanSerializerModifier() {
                @Override public JsonSerializer<?> modifySerializer(SerializationConfig config, BeanDescription desc, JsonSerializer<?> serializer) {
//                  return serializer;
                  return new JsonSerializer<Object>() {
                    @Override public void serialize(Object value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
                      ((JsonSerializer<Object>) serializer).serialize(value, gen, serializers);
                    }};
                }
            });
        }
    });
    
    
    System.out.println(
        mapper.writerWithDefaultPrettyPrinter().writeValueAsString(contact)
    );
    
  }
}

上面的代码除了注册一个 'custom' 序列化器(只是委托回原始序列化器)之外没有做任何其他事情,但是它产生 JSON 没有空属性:

{ "first" : "Bob", "last" : "Barker" }

如果您按 return serializer; 原样注释掉 return new JsonSerializer<Object>() {... 和 return 传入的序列化程序,则 Jackson 序列化空属性:

{ "first" : "Bob", "middle" : null, "last" : "Barker", "email" : null }


我已经阅读了许多看似相关的 SO 文章,但是 none 已经引导我找到了解决方案。我已经尝试在序列化时将映射器显式设置为 Include.ALWAYS,但没有成功。

我唯一的线索是 JsonSerializer 的 JavaDoc 中的评论:

NOTE: various serialize methods are never (to be) called with null values -- caller must handle null values, usually by calling {@link SerializerProvider#findNullValueSerializer} to obtain serializer to use.
This also means that custom serializers cannot be directly used to change
the output to produce when serializing null values.

我正在使用 Jackson 版本 2.11.2。


我的问题是:如何编写自定义序列化程序并让 Jackson 遵守其通常的关于 null 属性 序列化的包含指令?

上下文信息:我实际的自定义序列化程序的工作是有条件地隐藏序列化中的属性。我有一个自定义注释 @JsonAuth,它用 @JacksonAnnotationsInside @JsonInclude(Include.NON_EMPTY) 进行了元注释,我的自定义序列化程序(ContextualSerializer)在覆盖的 isEmpty 方法和 returns true(视为空)如果缺少授权。最终结果是我有一个可以应用于属性的注释,如果客户端未被授权,它将隐藏序列化中的 属性。除了...自定义序列化程序的使用具有丢弃所有空属性的意外副作用。


更新:Jackson 的 BeanPropertyWriter.serializeAsField(...) 方法将完全忽略分配给 属性 的任何自定义序列化程序(如果值为 null)。

我能够通过对 class 编写一个小扩展来覆盖此行为,这允许我的“isAuthorized”逻辑抢占空检查:

  public class JsonAuthPropertyWriter extends BeanPropertyWriter {
   
    private final Predicate<Object> authFilter; 
    
    private JsonAuthPropertyWriter(BeanPropertyWriter delegate, Predicate<Object> authFilter) {
      super(delegate);
      this.authFilter = authFilter;
      // set null serializer or authorized null values disappear
      super.assignNullSerializer(NullSerializer.instance);
    }
    
    @Override
    public void serializeAsField(
        Object bean,
        JsonGenerator gen,
        SerializerProvider prov) throws Exception {
      boolean authorized = authFilter.test(bean);
      if (!authorized) return;
      super.serializeAsField(bean, gen, prov);
    }
  }

我使用 BeanSerializerModifier:

注入了这些自定义 BeanPropertyWriters
  private static class JsonAuthBeanSerializerModifier extends BeanSerializerModifier {
    
    @Override
    public List<BeanPropertyWriter> changeProperties(
        SerializationConfig config,
        BeanDescription beanDesc, 
        List<BeanPropertyWriter> beanProperties
        ) {
      
      for (int i = 0; i < beanProperties.size(); i++) {
        BeanPropertyWriter beanPropertyWriter = beanProperties.get(i);
        JsonAuth jsonAuth = beanPropertyWriter.findAnnotation(JsonAuth.class);
        if (jsonAuth != null) {
          Predicate<Object> authPredicate = ...
          beanProperties.set(i, new JsonAuthPropertyWriter(beanPropertyWriter, authPredicate));
        }
      }
      return beanProperties;
    }
    
  }

我可能误解了你的意思,但这个方法似乎很有用:

import com.fasterxml.jackson.annotation.JsonFilter;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.ObjectWriter;
import com.fasterxml.jackson.databind.ser.BeanPropertyWriter;
import com.fasterxml.jackson.databind.ser.FilterProvider;
import com.fasterxml.jackson.databind.ser.PropertyWriter;
import com.fasterxml.jackson.databind.ser.impl.SimpleBeanPropertyFilter;
import com.fasterxml.jackson.databind.ser.impl.SimpleFilterProvider;
import java.lang.annotation.ElementType;
import java.lang.annotation.Retention;
import java.lang.annotation.RetentionPolicy;
import java.lang.annotation.Target;
import java.util.HashMap;
import java.util.Map;

public class Test2 {

    @Target(ElementType.FIELD)
    @Retention(RetentionPolicy.RUNTIME)
    @interface JsonAuth {

    }

    @JsonFilter("myFilter")
    public static class Contact {

        @JsonAuth
        String first;
        @JsonAuth
        String middle;
        @JsonAuth
        String last;
        String email;

        public Contact(String first, String middle, String last, String email) {
            this.first = first;
            this.middle = middle;
            this.last = last;
            this.email = email;
        }
        public String getFirst() {
            return first;
        }
        public void setFirst(String first) {
            this.first = first;
        }
        public String getMiddle() {
            return middle;
        }
        public void setMiddle(String middle) {
            this.middle = middle;
        }
        public String getLast() {
            return last;
        }
        public void setLast(String last) {
            this.last = last;
        }
        public String getEmail() {
            return email;
        }
        public void setEmail(String email) {
            this.email = email;
        }
    }
    public static Map<String,Boolean> fieldSerialisationCount = new HashMap<>();

    public static void main(String[] args) throws Exception {
        Contact contact = new Contact("Bob", null, "Barker", null);

        ObjectMapper mapper = new ObjectMapper();
        FilterProvider filters = new SimpleFilterProvider().addFilter("myFilter", new SimpleBeanPropertyFilter() {
            @Override
            protected boolean include(BeanPropertyWriter writer) {
                return super.include(writer) && isAuthed(writer);
            }
            @Override
            protected boolean include(PropertyWriter writer) {
                return super.include(writer) && isAuthed(writer);
            }

            private boolean isAuthed(PropertyWriter writer) {
                if (!writer.getMember().hasAnnotation(JsonAuth.class)) {
                    return true;
                } else {

                    return fieldSerialisationCount.compute(writer.getName(), (n, b) -> b == null ? true : !b); // check auth here
                }
            }
        });
        mapper.setFilterProvider(filters);
        ObjectWriter writer = mapper.writer(filters).withDefaultPrettyPrinter();

        System.out.println(
                writer.writeValueAsString(contact)
        );
        System.out.println(
                writer.writeValueAsString(contact)
        );
        System.out.println(
                writer.writeValueAsString(contact)
        );
    }
}

它每隔一段时间序列化带注释的字段,就像使用持久状态的过滤器示例一样。

请告诉我这是否适合你。

顺便说一下,我同意 Jackson 有你描述的问题,但我不知道如何解决它,所以这是一个解决方法,而不是对你原来问题的回答。