从 Gmail 获取电子邮件并将其写入文件的最快方法

Question

我正在制作一个脚本，它从我的 gmail 收件箱中获取 n 封电子邮件并将 n 个主题写入文本文件。虽然这目前工作正常。我正在寻找一种方法来获取例如 JSON 格式的 20 封电子邮件，只需一次调用，而不是在循环中一个接一个地发送。

目前我有这个：

from __future__ import print_function
import pickle
import os.path

from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly']

def main():
    """Shows basic usage of the Gmail API.
    Lists the user's Gmail labels.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server(port=0)
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('gmail', 'v1', credentials=creds)

    resultsMessages = service.users().messages().list(userId='me', labelIds=['INBOX']).execute()
    messages = resultsMessages.get('messages', [])

    f = open("output.txt", "a")

    message_count = int(input("How many messages do you want to write?"))

    if not messages:
        print("no messages found")
    else:
        print("messages:")
        for i, message in enumerate(messages[:message_count]):
            f.write("message "+ str(i))
            msg = service.users().messages().get(userId='me', id=message['id']).execute()
            headers = msg["payload"]["headers"]
            subject = [i['value'] for i in headers if i["name"] == "Subject"]
            f.write("subject: "+subject[0])
            f.write("\n")
    f.close()

if __name__ == '__main__':
    main()

这基本上是获取 100 封电子邮件的 ID，然后每封电子邮件获取主题并将其写入文件。它工作正常，但我想找到一种更快的方法。有什么方法可以让我只用一个电话就可以从服务器获得 n 封 JSON 格式的电子邮件？我想我的代码的瓶颈是调用 msg = service.users().messages().get(userId='me', id=message['id']).execute() 在循环中执行。

非常感谢

Answer 1

I just want to know if there is a way to get for instance 20 emails in JSON format with only one call.

如果您查看 gmail api 的文档，您会发现只有一种方法可以 returns 获取电子邮件的详细信息 Messages.get。 Message get 将单个消息 ID 作为参数，returns 返回有关该单个消息的信息。

无法将多个消息 ID 发送到 message.get。

如果您正在寻找减少网络流量的方法，您应该研究 batching 允许您将最多 100 message.get 发送到单个 http 请求的请求。

您仍然需要为您批量发送的每个请求支付配额费用。

从 Gmail 获取电子邮件并将其写入文件的最快方法

Fastest way to get emails from Gmail and write them into file

python

gmail

google-api

google-api-python-client

gmail-api