无法让我的代码重复问题让游戏继续
Can't get my code to repeat the questions for the game to continue
我必须为我正在服用的 class 编写代码。这是一款基于投注 2 种颜色和 1 - 36 数字的游戏。用户已经给了他们一定数量的筹码,即 100。我已经编写了大部分代码,但是,我无法获得我的重复该过程的代码。我目前正在使用 Do-While 循环。但这就是行不通。
这是我的代码:
import java.util.Scanner;
import java.lang.Math;
public class Program_8 {
public static void main(String[] args) {
Scanner userInput = new Scanner(System.in);
int chipsNow = 100;
int userChoice;
int chipsBetted = 0;
//welcome message
welcome();
do {
int spinNum = (int)(Math.random() * 36) + 0;
userChoice = getMenuChoice(userInput);
//get user choice
if (userChoice == 1) {
int getNum = getNumber(userInput);
int getBet = getBet(userInput, chipsNow);
String determineColor = determineColor(spinNum);
System.out.println("\nSpinning Wheel....");
System.out.println("Spin Number: " + spinNum);
System.out.println("Spin Color: " + determineColor);
if (getNum == spinNum) {
chipsNow += getBet;
chipsBetted += getBet;
System.out.println("Congrats, you won!");
System.out.println("\nYou now have: " + chipsNow + " chips");
;
}
else {
chipsNow -= getBet;
System.out.println("\nSorry, you lost!");
System.out.println("You now have: " + chipsNow + " chips");
}
}
if (userChoice == 2) {
String getColor = getColor(userInput);
int getBet = getBet(userInput, chipsNow);
String determineColor = determineColor(spinNum);
System.out.println("Spinning Wheel....");
System.out.println("Spin Number: " + spinNum);
System.out.println("Spin Color: " + determineColor);
if (getColor.equals(determineColor)) {
chipsNow += getBet;
chipsBetted += getBet;
System.out.println("\nCongrats, you won!");
System.out.println("You now have: " + chipsNow + " chips");
}
else {
chipsNow -= getBet;
System.out.println("\nSorry, you lost!");
System.out.println("You now have: " + chipsNow + " chips");
}
}
}while (userChoice != 3 && chipsNow > 0);
}
//welcome message
public static void welcome() {
int chipsNow = 100;
System.out.println("############################");
System.out.println("# Welcome To Roulette #");
System.out.println("############################");
System.out.println("# Number Bets Payout: 35:1 #");
System.out.println("# Color Bets Payout: 1:1 #");
System.out.println("############################\n");
System.out.println("Chips owned: " + chipsNow + "\n");
System.out.println("1. Pick a number to bet on");
System.out.println("2. Pick a color to bet on");
System.out.println("3. Cash Out\n");
}
//get menu choice
public static int getMenuChoice(Scanner userInput) {
int getMenuChoice;
System.out.println("\nChoose an option [1-3]: ");
getMenuChoice = userInput.nextInt();
return getMenuChoice;
}
public static int getNumber(Scanner userInput) {
int getNumber;
do {
System.out.println("Enter a number to bet on [0-36]: ");
getNumber = userInput.nextInt();
}while (getNumber < 0 || getNumber > 36);
return getNumber;
}
public static String getColor(Scanner userInput) {
String getColor = "";
do{
System.out.println("Enter a color to bet on [Red or Black]: ");
getColor = userInput.next();
}while (!(getColor.equals("Red") || getColor.equals("Black")));
return getColor;
}
public static int getBet(Scanner userInput, int chipsNow) {
int getBet;
do{
System.out.println("Enter the number of chips to bet [1 - " + chipsNow + "]: ");
getBet = userInput.nextInt();
}while (getBet < 1 || getBet > chipsNow);
return getBet;
}
public static String determineColor(int spinNum) {
if (spinNum % 2 == 0) {
if (spinNum == 0) {
return "Green";
}
//even
else {
return "Red";
}
}
return "Black";
}
public static void report(int chipsNow) {
System.out.println("\nThanks for Playing!");
System.out.println("You Won a total of: " + chipsNow + " chips today");
}
}
所以只看代码我会:
在 do while 之外声明 int userChoice = 0;
。这是 while 条件起作用所必需的。
welcome();
和 userChoice = getMenuChoice(userInput);
应该进入 do while 因此它将重复欢迎消息并要求用户选择在执行时执行的所有操作
像这样简化你的 while 循环 while(userChoice != 3 && chipsNow > 0)
。这只是为了使其更具可读性。
最后删除 if(getNum == spinNum) { } else { }
中的 break;
。 break
将强制退出 while 循环,而不管 while 条件是否满足。所以基本上,如果你赢了或输了一场比赛,你的循环就会退出,我认为这不是你想要的。您只希望在 chipsNow < 0
或 userChoice == 3
时退出循环
我必须为我正在服用的 class 编写代码。这是一款基于投注 2 种颜色和 1 - 36 数字的游戏。用户已经给了他们一定数量的筹码,即 100。我已经编写了大部分代码,但是,我无法获得我的重复该过程的代码。我目前正在使用 Do-While 循环。但这就是行不通。
这是我的代码:
import java.util.Scanner;
import java.lang.Math;
public class Program_8 {
public static void main(String[] args) {
Scanner userInput = new Scanner(System.in);
int chipsNow = 100;
int userChoice;
int chipsBetted = 0;
//welcome message
welcome();
do {
int spinNum = (int)(Math.random() * 36) + 0;
userChoice = getMenuChoice(userInput);
//get user choice
if (userChoice == 1) {
int getNum = getNumber(userInput);
int getBet = getBet(userInput, chipsNow);
String determineColor = determineColor(spinNum);
System.out.println("\nSpinning Wheel....");
System.out.println("Spin Number: " + spinNum);
System.out.println("Spin Color: " + determineColor);
if (getNum == spinNum) {
chipsNow += getBet;
chipsBetted += getBet;
System.out.println("Congrats, you won!");
System.out.println("\nYou now have: " + chipsNow + " chips");
;
}
else {
chipsNow -= getBet;
System.out.println("\nSorry, you lost!");
System.out.println("You now have: " + chipsNow + " chips");
}
}
if (userChoice == 2) {
String getColor = getColor(userInput);
int getBet = getBet(userInput, chipsNow);
String determineColor = determineColor(spinNum);
System.out.println("Spinning Wheel....");
System.out.println("Spin Number: " + spinNum);
System.out.println("Spin Color: " + determineColor);
if (getColor.equals(determineColor)) {
chipsNow += getBet;
chipsBetted += getBet;
System.out.println("\nCongrats, you won!");
System.out.println("You now have: " + chipsNow + " chips");
}
else {
chipsNow -= getBet;
System.out.println("\nSorry, you lost!");
System.out.println("You now have: " + chipsNow + " chips");
}
}
}while (userChoice != 3 && chipsNow > 0);
}
//welcome message
public static void welcome() {
int chipsNow = 100;
System.out.println("############################");
System.out.println("# Welcome To Roulette #");
System.out.println("############################");
System.out.println("# Number Bets Payout: 35:1 #");
System.out.println("# Color Bets Payout: 1:1 #");
System.out.println("############################\n");
System.out.println("Chips owned: " + chipsNow + "\n");
System.out.println("1. Pick a number to bet on");
System.out.println("2. Pick a color to bet on");
System.out.println("3. Cash Out\n");
}
//get menu choice
public static int getMenuChoice(Scanner userInput) {
int getMenuChoice;
System.out.println("\nChoose an option [1-3]: ");
getMenuChoice = userInput.nextInt();
return getMenuChoice;
}
public static int getNumber(Scanner userInput) {
int getNumber;
do {
System.out.println("Enter a number to bet on [0-36]: ");
getNumber = userInput.nextInt();
}while (getNumber < 0 || getNumber > 36);
return getNumber;
}
public static String getColor(Scanner userInput) {
String getColor = "";
do{
System.out.println("Enter a color to bet on [Red or Black]: ");
getColor = userInput.next();
}while (!(getColor.equals("Red") || getColor.equals("Black")));
return getColor;
}
public static int getBet(Scanner userInput, int chipsNow) {
int getBet;
do{
System.out.println("Enter the number of chips to bet [1 - " + chipsNow + "]: ");
getBet = userInput.nextInt();
}while (getBet < 1 || getBet > chipsNow);
return getBet;
}
public static String determineColor(int spinNum) {
if (spinNum % 2 == 0) {
if (spinNum == 0) {
return "Green";
}
//even
else {
return "Red";
}
}
return "Black";
}
public static void report(int chipsNow) {
System.out.println("\nThanks for Playing!");
System.out.println("You Won a total of: " + chipsNow + " chips today");
}
}
所以只看代码我会:
在 do while 之外声明
int userChoice = 0;
。这是 while 条件起作用所必需的。welcome();
和userChoice = getMenuChoice(userInput);
应该进入 do while 因此它将重复欢迎消息并要求用户选择在执行时执行的所有操作像这样简化你的 while 循环
while(userChoice != 3 && chipsNow > 0)
。这只是为了使其更具可读性。最后删除
时退出循环if(getNum == spinNum) { } else { }
中的break;
。break
将强制退出 while 循环,而不管 while 条件是否满足。所以基本上,如果你赢了或输了一场比赛,你的循环就会退出,我认为这不是你想要的。您只希望在chipsNow < 0
或userChoice == 3