在 R 中构建网络

Question

我有一个如下所示的 csv 文件：

"","people_id","commit_id"
 "1",1,0
 "2",1,117
 "3",1,144
 "4",1,278
 …

Here's 如果您想查看 csv 文件。它包含 11735 行，但包含 5923 个唯一的人员 ID。

有谁知道如何将人员 ID 与常见的 "commit_id" 联系起来并忽略 commit_id 0，因为 ID 0 不存在。

目前我已经这样做了：

# read the csv file 
commitsNetwork <- read.csv("commits.csv", header=TRUE)

# use a subset for demo purpose

commitsNetwork <- commitsNetwork[c("people_id", "commit_id")]

#build edgelist(for commits)
C <- spMatrix(nrow = length(unique(commitsNetwork$people_id)),
              ncol = length(unique(commitsNetwork$commit_id)),
              i = as.numeric(factor(commitsNetwork$people_id)),
              j = as.numeric(factor(commitsNetwork$commit_id)),
              x = rep(1, length(as.numeric(commitsNetwork$people_id))) )
row.names(C) <- levels(factor(commitsNetwork$people_id))
colnames(C) <- levels(factor(commitsNetwork$commit_id))
adjC <- tcrossprod(C) 
comG <- graph.adjacency(adjC, mode = "undirected", weighted = TRUE, diag = FALSE)

#write to pajek file
write.graph(comG, "comNetwork.net", format = "pajek")

此外，边缘来自第 2 列 "commit_id"。如果两个顶点（人）都由第 6 列的公共 commit_id 连接。

因此我不确定如何在 R 中使用此 csv 文件生成网络。

理想的输出应该是这样的：

*顶点数 5923 1

2

3

4

...

*边

1 4 1

1 25 1

1 39 1

1 41 1

1 48 1

直到 5923...

Answer 1

也许你想要这样的东西：

library(igraph)
library(Matrix)

download.file("https://www.dropbox.com/s/q7sxfwjec97qzcy/people.csv?dl=1", 
              tf <- tempfile(fileext = ".csv"), mode = "wb")
people <- read.csv(tf)

A <- spMatrix(nrow = length(unique(people$people)),
              ncol = length(unique(people$repository_id)),
              i = as.numeric(factor(people$people)),
              j = as.numeric(factor(people$repository_id)),
              x = rep(1, length(as.numeric(people$people))) )
row.names(A) <- levels(factor(people$people))
colnames(A) <- levels(factor(people$repository_id))
adj <- tcrossprod(A) 
g <- graph.adjacency(adj, mode = "undirected", weighted = TRUE, diag = FALSE)

另见 here。

在 R 中构建网络

Building network in R

r

csv

igraph

vertices

edges