使用迭代器从 [1, 2, 3] 中获取特定的列表序列

Question

我想实现这个输出

[(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)]

来自这个给定的列表：[1,2,3]。

我试过使用

foo = [1, 2, 2]
print(list(permutations(foo, 3)))

还有这个

l

ist(it.combinations_with_replacement([1,2,3], 3))

from itertools import combinations 
  
def rSubset(arr, r): 
   
    return list(combinations(arr, r)) 
  
 
if __name__ == "__main__": 
    arr = [1, 2, 3] 
    r = 3
    print (rSubset(arr, r))

但我无法获得所需的结果，请提供任何帮助

Answer 1

您想要产品，而不是排列或组合。

from itertools import product

print(list(product([1,2,3], repeat=3)))

使用迭代器从 [1, 2, 3] 中获取特定的列表序列

using Iterators to get a particular sequence of list from [1, 2, 3]

python

combinations

permutation

itertools