通讯录阅读时间 Android
Contact book read time on Android
我编写了以下查询以从设备读取联系人。
private fun getContactPhoneNumbers(resolver: ContentResolver): Map<String, NameAndPhoneList> {
val startTime = System.nanoTime()
val map = hashMapOf<String, NameAndPhoneList>()
val projection = arrayOf(
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
ContactsContract.Contacts.PHOTO_THUMBNAIL_URI
)
val selection =
"${ContactsContract.Contacts.DISPLAY_NAME} NOT LIKE '' and ${ContactsContract.Contacts.DISPLAY_NAME} NOT NULL"
resolver.query(
ContactsContract.Contacts.CONTENT_URI,
projection,
selection,
null,
null,
null
)?.let { cursor ->
if (cursor.count > 0) {
while (cursor.moveToNext()) {
val id: String? =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID))
val name: String? =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME))
val photoUri =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.PHOTO_THUMBNAIL_URI))
val phone =
if (cursor.getInt(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
val pCur: Cursor = resolver.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
arrayOf(id),
null
)!!
val numbers = mutableListOf<String>()
while (pCur.moveToNext()) {
val phoneNo: String = pCur.getString(
pCur.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.NUMBER
)
)
numbers.add(phoneNo)
}
pCur.close()
numbers
} else
null
// take contacts which either have email or phone numbers
if (id != null && name != null) {
map[id] = NameAndPhoneList(name, phone, photoUri?.let { Uri.parse(it) })
}
}
}
cursor.close()
}
val endTime = System.nanoTime() - startTime
Timber.i("$CONTACT_SYNC_PHONE_MAP_QUERY_TIME = $endTime")
return map
}
private data class NameAndPhoneList(
val name: String,
val phoneList: List<String>?,
val imageUri: Uri?
)
对于长度为 6,300 个联系人的电话簿,这需要 112877872699 纳秒(~2 分钟)。这是预期的还是我们可以进一步优化?
对于 6,300 个联系人(假设所有人都有一个 phone),您要进行 6,301 个查询,这就是为什么它这么慢的原因...
相反,您可以受益于 ContactsContract 的“implicit join”功能,它允许您在查询 Data.CONTENT_URI
table.[=16= 时获取 Contacts.CONTENT_URI
字段]
所以,直接查询数据table,得到所有phone包括CONTACT_ID
、DISPLAY_NAME
等字段,然后放入一些地图联系人 ID => 数据。
Java 中的示例代码可以提供帮助 -
我编写了以下查询以从设备读取联系人。
private fun getContactPhoneNumbers(resolver: ContentResolver): Map<String, NameAndPhoneList> {
val startTime = System.nanoTime()
val map = hashMapOf<String, NameAndPhoneList>()
val projection = arrayOf(
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
ContactsContract.Contacts.PHOTO_THUMBNAIL_URI
)
val selection =
"${ContactsContract.Contacts.DISPLAY_NAME} NOT LIKE '' and ${ContactsContract.Contacts.DISPLAY_NAME} NOT NULL"
resolver.query(
ContactsContract.Contacts.CONTENT_URI,
projection,
selection,
null,
null,
null
)?.let { cursor ->
if (cursor.count > 0) {
while (cursor.moveToNext()) {
val id: String? =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID))
val name: String? =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME))
val photoUri =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.PHOTO_THUMBNAIL_URI))
val phone =
if (cursor.getInt(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
val pCur: Cursor = resolver.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
arrayOf(id),
null
)!!
val numbers = mutableListOf<String>()
while (pCur.moveToNext()) {
val phoneNo: String = pCur.getString(
pCur.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.NUMBER
)
)
numbers.add(phoneNo)
}
pCur.close()
numbers
} else
null
// take contacts which either have email or phone numbers
if (id != null && name != null) {
map[id] = NameAndPhoneList(name, phone, photoUri?.let { Uri.parse(it) })
}
}
}
cursor.close()
}
val endTime = System.nanoTime() - startTime
Timber.i("$CONTACT_SYNC_PHONE_MAP_QUERY_TIME = $endTime")
return map
}
private data class NameAndPhoneList(
val name: String,
val phoneList: List<String>?,
val imageUri: Uri?
)
对于长度为 6,300 个联系人的电话簿,这需要 112877872699 纳秒(~2 分钟)。这是预期的还是我们可以进一步优化?
对于 6,300 个联系人(假设所有人都有一个 phone),您要进行 6,301 个查询,这就是为什么它这么慢的原因...
相反,您可以受益于 ContactsContract 的“implicit join”功能,它允许您在查询 Data.CONTENT_URI
table.[=16= 时获取 Contacts.CONTENT_URI
字段]
所以,直接查询数据table,得到所有phone包括CONTACT_ID
、DISPLAY_NAME
等字段,然后放入一些地图联系人 ID => 数据。
Java 中的示例代码可以提供帮助 -