我如何将两个列表放在一起，但在 Python 中 TURN-BY-TURN

Question

我有这个列表：

a = ["1 Monday","1 Wednesday","1 Friday"]
b = ["2 Tuesday","2 Thursday","2 Saturday"]

我想将这些结合起来：

c = ["1 Monday", "2 Tuesday", "1 Wednesday", "2 Thursday", "1 Friday", "2 Saturday"]

我想轮流做这个。因此，附加 a 的第一个元素和 b 的第一个元素，然后附加 a 的第二个元素和 b 的第二个元素等。

Answer 1

您可以将 itertools 与 zip 一起使用：

In [3585]: import itertools

In [3586]: list(itertools.chain(*zip(a,b)))
Out[3586]: 
['1 Monday',
 '2 Tuesday',
 '1 Wednesday',
 '2 Thursday',
 '1 Friday',
 '2 Saturday']

Answer 2

基本解

list_turn = []
a = ["1 Monday","1 Wednesday","1 Friday"]
b = ["2 Tuesday","2 Thursday","2 Saturday"]
for i in range(len(a)):
    list_turn.append(a[i])
    list_turn.append(b[i])

我如何将两个列表放在一起，但在 Python 中 TURN-BY-TURN

How do I put two list together as one but TURN-BY-TURN in Python

python

list

concatenation

python-3.x

turn-by-turn