如何在 selenium 中使用 xpath 获取元素的父元素 (python)

Question

我有一个脚本可以在网页上获取我想要的所有图像，然后我必须获取包含 image.

的 link

我实际上点击了每张图片，选择了当前页面 link 然后我返回并继续工作。这很慢，但我有一个 a 标签“拥抱”我的 image，我不知道如何检索该标签。使用标签，它可以更容易和更快。我附上 html 代码和我的 python 代码！

HTML代码

<div class="col-xl col-lg col-md-4 col-sm-6 col-6">
<a href="URL I WANT TO GET ">
<article>
<span class="year">2017</span>
<span class="quality">4K</span>
<span class="imdb">6.7</span>
<img width="190" height="279" src="THE IMAGE URL" class="img-full wp-post-image" alt="" loading="lazy"> <h2>TITLE</h2>
</article>
</a></div>
<div class="col-xl col-lg col-md-4 col-sm-6 col-6">
<a href="URL I WANT TO GET 2">
<article>
<span class="year">2019</span>
<span class="quality">4K</span>
<span class="imdb">8.0</span>
<img width="190" height="279" src="THE IMAGE URL 2" class="img-full wp-post-image" alt="" loading="lazy"> <h2>TITLE</h2>
</article>
</a></div>

Python代码

self.driver.get(category_url)
WebDriverWait(self.driver, 10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, 'div.archivePaging')))  # a div to see if page is loaded
movies_buttons = self.driver.find_elements_by_css_selector('img.img-full.wp-post-image')

print("Getting all the links!")
for movie in movies_buttons:
    self.driver.execute_script("arguments[0].scrollIntoView();", movie)
    movie.click()
    WebDriverWait(self.driver, 10).until(EC.visibility_of_element_located((By.CLASS_NAME, 'infoFilmSingle')))
    print(self.driver.current_url)
    self.driver.back()
    WebDriverWait(self.driver, 10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, 'div.archivePaging')))

请注意，此代码现在不起作用，因为我正在调用旧页面的电影对象，但这不是问题，因为如果我只看到 link，则不需要更改页面等会话不会改变。

Answer 1

根据我的理解你想做的一个例子 - 你想获得父 a 标签 href

例子

from selenium import webdriver
driver = webdriver.Chrome(executable_path=r'C:\Program Files\ChromeDriver\chromedriver.exe')

html_content = """
<div class="col-xl col-lg col-md-4 col-sm-6 col-6">
    <a href="https://www.link1.de">
        <article>
            <span class="year">2017</span>
            <span class="quality">4K</span>
            <span class="imdb">6.7</span>
            <img width="190" height="279" src="THE IMAGE URL" class="img-full wp-post-image" alt="" loading="lazy"> <h2>TITLE</h2>
        </article>
    </a>
</div>
<div class="col-xl col-lg col-md-4 col-sm-6 col-6">
    <a href="https://www.link2.de">
        <article>
            <span class="year">2019</span>
            <span class="quality">4K</span>
            <span class="imdb">8.0</span>
            <img width="190" height="279" src="THE IMAGE URL 2" class="img-full wp-post-image" alt="" loading="lazy"> <h2>TITLE</h2>
        </article>
    </a>
</div>
"""
driver.get("data:text/html;charset=utf-8,{html_content}".format(html_content=html_content))

找到 image elements 及其 class 并向上移动带有 .. 的元素结构，在本例中为 /../..

driver.get("data:text/html;charset=utf-8,{html_content}".format(html_content=html_content))
aTags = driver.find_elements_by_xpath("//img[contains(@class,'img-full wp-post-image')]/../..")
for ele in aTags:
  x=ele.get_attribute('href')
  print(x)
driver.close()

输出

https://www.link1.de/
https://www.link2.de/

如何在 selenium 中使用 xpath 获取元素的父元素 (python)

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