python 处理来自用户的无效输入

Question

我被这个作业卡住了：

rewrite the following program so that it can handle any invalid inputs from user.

def example():
   for i in range(3)
       x=eval(input('Enter a number: '))
       y=eval(input('enter another one: '))
       print(x/y)

我试过尝试了 try... 除了 ValueError，但程序仍然无法运行。

Answer 1

def example():

   for i in range(3)
      try:
         x=eval(input('Enter a number: '))
      except ValueError:
         print("Sorry, value error")
      try:
         y=eval(input('enter another one: '))
      except ValueError:
         print("Sorry, value error")`enter code here`
      try:
         print(x/y)
      except ValueError:
         print("Sorry, cant divide zero")

Answer 2

那是因为你可能没有考虑到 y = 0 时得到的 ZeroDivisionError！怎么样

def example():
   for i in range(3):
      correct_inputs = False
      while not correct_inputs:
         try:
            x=eval(input('Enter a number: '))
            y=eval(input('enter another one: '))
            print(x/y)
            correct_inputs = True
         except:
            print("bad input received")
            continue

此函数正好计算出 3 个正确的除法 x/y！如果您需要有关 continue 运算符的良好参考，请查看 here

python 处理来自用户的无效输入

python handling invalid inputs from a user

python

error-handling

exception

invalid-characters