可能吗？按 Visit.VstMobile 分组，具有 ( (count(Visit.VstMobile)) >1 多个选项

Question

让我知道这在 mysql 查询中是否可行：我在 Whosebug 中提到了更多选项。

分组 Visit.VstMobile 具有 ( (count(Visit.VstMobile)>=0 和 count(Visit.VstMobile)<=10) 或 (count(Visit.VstMobile)>=10 和 count(Visit.VstMobile)< =20))

我有一个范围 selection 和多个 select 比如：

[0-10]

[10-20]

[20+]

我可以在上面的下拉列表中 select 多个选项。

基于这个 post 值，我必须在 having 子句中形成查询。如果还有其他选择，请告诉我。

这是我的查询：

select Distinct(Visit.VstMobile) as mobile, count(VstMobile) as cnt from Visit inner join centertemp on Visit.RegistrationCentreCode=centertemp.SysNo inner join patient on Visit.VstPatCode=patient.Patcode inner join result on result.TrJobCode=Visit.VstCode inner join Test on Test.TestCode=result.TrTestCode inner join Param on Param.ParamCode=result.TrParamCode ----[some where conditions]---- group by Visit.VstMobile having ( (count(Visit.VstMobile)>=0 and count(Visit.VstMobile)<=10) or (count(Visit.VstMobile)>=10 and count(Visit.VstMobile)<=20))

-- 没有返回一行。

Answer 1

根据您的 fiddle，我了解到范围的数量可能会有所不同。因此 having 子句中的条件数量可能会有所不同。因此，最简单的选择是根据用户输入在代码中动态编写查询并执行查询。这是一个可能的解决方案：

<?php
$range1 = "2-5"; //get from user 
$range2 = "5-10"; //get from user 
$range3 = ""; //get from user

$sql = "SELECT VstMobile, count(VstMobile) as cnt FROM Venkatesh group by VstMobile ";

//all ranges are optional, hence check if we need having clause
if($range1 != "" or $range2 == "" or $range3 ==""){
    $sql = $sql . " having ("

    if($range1 != ""){
        $val1 = explode('-',$range1);
        $sql = $sql . " (count(VstMobile) >=". $val1[0] . "and count(VstMobile) <= ".$val1[1].")";
    }
    if($range2 != ""){
        $val2 = explode('-',$range2);
        //check previous condition string exists before adding 'or' condition
        if($range1 != ""){
            $sql .= " or ";
        }
        $sql = $sql . " (count(VstMobile) >=". $val2[0] . "and count(VstMobile) <= ".$val2[1].")";
    }
    if($range3 != ""){
        $val3 = explode('-',$range3);
        //check previous condition string exists before adding 'or' condition
        if($range2 != "" or $range1 != ""){
            $sql .= " or ";
        }
        $sql = $sql . " (count(VstMobile) >=". $val3[0] . "and count(VstMobile) <= ".$val3[1].")";
    }
    $sql = $sql . " )"          
}

$result = $conn->query($sql);

?>

我不太擅长php，但是既然你标记了php，我就尝试了，所以如果有语法错误请原谅，我希望你能理解它的基本思想。

来自德鲁的编辑

CREATE TABLE Venkatesh (VstMobile varchar(10));



INSERT INTO Venkatesh (`VstMobile`) VALUES ('1234567890'),('1234567890'),('1223345547'),('1223345547');
('9876543210'),('9876543210'),('1223345547'),('1223345547');
('9876543210'),('9876543210'),('9876543210'),('9876543201');
('9876543201'),('9876543201');



// select vstmobile,count(*) 
// from Venkatesh 
// group by vstmobile



SELECT VstMobile, 
count(VstMobile) as cnt 
FROM Venkatesh 
group by VstMobile 
having (
(count(VstMobile)>=0 and count(VstMobile) <=10) 

or (count(Vstmobile)>=10 and count(VstMobile)<=20) 

or (count(Vstmobile)>=20));

-- counts for all



SELECT VstMobile, 
count(VstMobile) as cnt 
FROM Venkatesh 
group by VstMobile 
having (

(count(VstMobile)>=0 and count(VstMobile) <=10) 

or (count(Vstmobile)>=20));

-- counts for all



SELECT VstMobile, 
count(VstMobile) as cnt 
FROM Venkatesh 
group by VstMobile 
having (
(count(Vstmobile)>=20));

-- 0 rows

效果很好有什么问题？

可能吗？按 Visit.VstMobile 分组，具有 ( (count(Visit.VstMobile)) >1 多个选项

Is it possible? group by Visit.VstMobile having ( (count(Visit.VstMobile)) >1 for multiple options

php

mysql

phpmyadmin

having-clause

multiple-conditions